'too many values to unpack', iterating over a dict. key=>string, value=>list

Question

I am getting the too many values to unpack error. Any idea how I can fix this?

first_names = ['foo', 'bar']
last_names = ['gravy', 'snowman']

fields = {
    'first_names': first_names,
    'last_name': last_names,
}        

for field, possible_values in fields:  # error happens on this line

Asked By: tipu

||

Source

Answer 1

Python 3

Use items().

for field, possible_values in fields.items():
    print(field, possible_values)

Python 2

Use iteritems().

for field, possible_values in fields.iteritems():
    print field, possible_values

See this answer for more information on iterating through dictionaries, such as using items(), across Python versions.

For reference, iteritems() was removed in Python 3.

Answered By: Philip Southam

Answer 2

You want to use iteritems. This returns an iterator over the dictionary, which gives you a tuple(key, value)

>>> for field, values in fields.iteritems():
...     print field, values
... 
first_names ['foo', 'bar']
last_name ['gravy', 'snowman']

Your problem was that you were looping over fields, which returns the keys of the dictionary.

>>> for field in fields:
...     print field
... 
first_names
last_name

Answered By: Mike Lewis

Answer 3

For Python 3.x iteritems has been removed. Use items instead.

for field, possible_values in fields.items():
    print(field, possible_values)

Answered By: Meistro

Answer 4

For lists, use enumerate

for field, possible_values in enumerate(fields):
    print(field, possible_values)

iteritems will not work for list objects

Answered By: Jordan

Answer 5

Can’t be iterating directly in dictionary. So you can through converting into tuple.

first_names = ['foo', 'bar']
last_names = ['gravy', 'snowman']

fields = {
    'first_names': first_names,
    'last_name': last_names,
         } 
tup_field=tuple(fields.items())
for names in fields.items():
     field,possible_values = names
     tup_possible_values=tuple(possible_values)
     for pvalue in tup_possible_values:
           print (field + "is" + pvalue)

Answered By: satya narayan pardhi

Answer 6

you are missing fields.iteritems() in your code.

You could also do it other way, where you get values using keys in the dictionary.

for key in fields:
    value = fields[key]

Answered By: Vaibhav Desai

Answer 7

In Python3 iteritems() is no longer supported

Use .items

for field, possible_values in fields.items():
    print(field, possible_values)

Answered By: ishandutta2007

Answer 8

Just thought I’d throw this in. I have the "too many values to unpack (expected 2)" crop up today. Infuriating but is was due to missing a comma in a choice list.

CapTextureChoices = [
("initial", ""),
("Shaggy", "Shaggy"),
("Wrinkled", "Wrinkled"),
("Striate," "Striate"),
("Downy", "Downy")
]

the missing comma between "Striate," "Striate" was the culprit

Answered By: benleroter

'too many values to unpack', iterating over a dict. key=>string, value=>list

Question:

Answers:

Python 3

Python 2