create a list of word lengths for the words in original_str using the accumulation pattern
Question:
The questions is this:
Write code to create a list of word lengths for the words in original_str using the accumulation pattern and assign the answer to a variable num_words_list. (You should use the len function).
original_str = "The quick brown rhino jumped over the extremely lazy fox".split()
original_list = list(original_str)
num_words = len(original_list)
for i in original_list:
print(len(i))
This is my output but it needs to be as a list and in the num_words_list variable, but I can’t seem to convert it.
3
5
5
5
6
4
3
9
4
3
Answers:
Without giving too much away:
- Create an empty list before your loop
- Instead of calling
print on each item, add the item to the list.
Both steps should be quite easy to find online.
Good luck!
Hi I think this is what you’re looking for?
original_str = "The quick brown rhino jumped over the extremely lazy fox".split()
original_list = list(original_str)
num_words = len(original_list)
num_words_list = []
for i in original_list:
num_words_list.append((len(i)))
print(num_words_list)
You could append each integer to an empty list, that way you should be okay 🙂
But a quick search in this general direction will have you figure this out in no time, best of luck!
original_str = "The quick brown rhino jumped over the extremely lazy fox"
original_list = list(original_str.split())
num_words = len(original_list)
num_words_list = []
for i in original_list:
num_words_list.append((len(i)))
print(num_words_list)
You could also use split() method, which transforms a string into a list of words.
original_str = "The quick brown rhino jumped over the extremely lazy fox."
split_str = original_str.split()
num_words_list=[]
for words in split_str:
num_words_list.append(len(words))
original_str = "The quick brown rhino jumped over the extremely lazy fox"
abc = original_str.split(" ")
num_words_list = []
for i in abc:
b = len(i)
num_words_list.append(b)
print(num_words_list)
You can do the same just in one line using Python list comprehension:
original_str = "The quick brown rhino jumped over the extremely lazy fox".split()
print([len(word) for word in original_str])
Answer:
original_str = "The quick brown rhino jumped over the extremely lazy fox"
original_list = list(original_str.split())
num_words_list = []
for i in original_list:
num_words_list.append((len(i)))
print(num_words_list)
First split the string into a list. Then create an empty list, start a for loop and append the length of the words:
original_str = "The quick brown rhino jumped over the extremely lazy fox"
num_words_list1 = original_str.split(" ")
num_words_list = []
for i in num_words_list1:
num_words_list.append(len(i))
print(num_words_list)
You can try the following codes as well
original_str = "The quick brown rhino jumped over the extremely lazy fox"
splt = original_str.split(" ")
print(splt)
count = 0
num_words_list = []
for i in splt:
num_words_list.append(len(i))
print(num_words_list)
The output is
['The', 'quick', 'brown', 'rhino', 'jumped', 'over', 'the', 'extremely', 'lazy', 'fox']
[3, 5, 5, 5, 6, 4, 3, 9, 4, 3]
Hope it helps!
original_str = "The quick brown rhino jumped over the extremely lazy fox"
num_words_list = []
for num in original_str.split():
num_words_list += [len(num)]
print(num_words_list)
original_str = "The quick brown rhino jumped over the extremely lazy fox"
original_str_list = original_str.split()
num_words_list = []
for word in original_str_list:
num_words_list.append(len(word))
#1. This is original string
#2. Here, we convert words in string to individual elements in list
#2. [‘The’, ‘quick’, ‘brown’, ‘rhino’, ‘jumped’, ‘over’, ‘the’, ‘extremely’, ‘lazy’, ‘fox’]
#3. Creating empty list to hold length of each word
#4. for loop to iterate over every element (word) in element
#4. for loop working – First it calculates length of every element in list one by one and then appends this length to num_words_list varaible
The questions is this:
Write code to create a list of word lengths for the words in original_str using the accumulation pattern and assign the answer to a variable num_words_list. (You should use the len function).
original_str = "The quick brown rhino jumped over the extremely lazy fox".split()
original_list = list(original_str)
num_words = len(original_list)
for i in original_list:
print(len(i))
This is my output but it needs to be as a list and in the num_words_list variable, but I can’t seem to convert it.
3
5
5
5
6
4
3
9
4
3
Without giving too much away:
- Create an empty list before your loop
- Instead of calling
printon each item, add the item to the list.
Both steps should be quite easy to find online.
Good luck!
Hi I think this is what you’re looking for?
original_str = "The quick brown rhino jumped over the extremely lazy fox".split()
original_list = list(original_str)
num_words = len(original_list)
num_words_list = []
for i in original_list:
num_words_list.append((len(i)))
print(num_words_list)
You could append each integer to an empty list, that way you should be okay 🙂
But a quick search in this general direction will have you figure this out in no time, best of luck!
original_str = "The quick brown rhino jumped over the extremely lazy fox"
original_list = list(original_str.split())
num_words = len(original_list)
num_words_list = []
for i in original_list:
num_words_list.append((len(i)))
print(num_words_list)
You could also use split() method, which transforms a string into a list of words.
original_str = "The quick brown rhino jumped over the extremely lazy fox."
split_str = original_str.split()
num_words_list=[]
for words in split_str:
num_words_list.append(len(words))
original_str = "The quick brown rhino jumped over the extremely lazy fox"
abc = original_str.split(" ")
num_words_list = []
for i in abc:
b = len(i)
num_words_list.append(b)
print(num_words_list)
You can do the same just in one line using Python list comprehension:
original_str = "The quick brown rhino jumped over the extremely lazy fox".split()
print([len(word) for word in original_str])
Answer:
original_str = "The quick brown rhino jumped over the extremely lazy fox"
original_list = list(original_str.split())
num_words_list = []
for i in original_list:
num_words_list.append((len(i)))
print(num_words_list)
First split the string into a list. Then create an empty list, start a for loop and append the length of the words:
original_str = "The quick brown rhino jumped over the extremely lazy fox"
num_words_list1 = original_str.split(" ")
num_words_list = []
for i in num_words_list1:
num_words_list.append(len(i))
print(num_words_list)
You can try the following codes as well
original_str = "The quick brown rhino jumped over the extremely lazy fox"
splt = original_str.split(" ")
print(splt)
count = 0
num_words_list = []
for i in splt:
num_words_list.append(len(i))
print(num_words_list)
The output is
['The', 'quick', 'brown', 'rhino', 'jumped', 'over', 'the', 'extremely', 'lazy', 'fox']
[3, 5, 5, 5, 6, 4, 3, 9, 4, 3]
Hope it helps!
original_str = "The quick brown rhino jumped over the extremely lazy fox"
num_words_list = []
for num in original_str.split():
num_words_list += [len(num)]
print(num_words_list)
original_str = "The quick brown rhino jumped over the extremely lazy fox"
original_str_list = original_str.split()
num_words_list = []
for word in original_str_list:
num_words_list.append(len(word))
#1. This is original string
#2. Here, we convert words in string to individual elements in list
#2. [‘The’, ‘quick’, ‘brown’, ‘rhino’, ‘jumped’, ‘over’, ‘the’, ‘extremely’, ‘lazy’, ‘fox’]
#3. Creating empty list to hold length of each word
#4. for loop to iterate over every element (word) in element
#4. for loop working – First it calculates length of every element in list one by one and then appends this length to num_words_list varaible