Docker: provide custom context in python-sdk

Question

I am trying to emulate the following CLI command using the docker python-sdk:

docker build -t mytag -f path_to_my_dockerfile/Dockerfile ../../../.

So in this case I want it to build the Dockerfile using the build context ../../../..
I tried using the python-sdk for docker but it seems each time the build context is not the right one, I tried various combinations like :

import docker
client = docker.from_env()
clients.images.build(path="../../../.", fileobj="path_to_my_dockerfile/Dockerfile", tag="mytag")

but nothing seems to work. Looking into the docker-py repo is not helping.

Asked By: jeandut

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Source

Answer 1

You just need to provide the dockerfile argument:

clients.images.build(
    path="../../../.",
    dockerfile="path_to_my_dockerfile/Dockerfile",
    tag="mytag"
)

Note that the dockerfile should be relative to path, not your current working directory.

If you have dockerfile and context relative to your current working directory, you may be able to compute the relative path with something like this:

dockerfile = pathlib.Path(os.path.normpath(dockerfile)).absolute()
context = pathlib.Path(os.path.normpath(context)).absolute()

path = dockerfile.relative_to(context)

Alternatively, you can also provide a custom build context, by creating a tarfile yourself with custom_context. This is the most flexible way, as you don’t even need a filesystem that way.

Answered By: Lie Ryan

Docker: provide custom context in python-sdk

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