Sendmail Errno[61] Connection Refused
Question:
I’ve been trying to get my application to mail some outputted text to an email. For simplification I have isolated the script :
import smtplib
import sys
import os
SERVER = "localhost"
FROM = os.getlogin()
TO = [raw_input("To : ")]
SUBJECT = "Message From " + os.getlogin()
print "Message : (End with ^D)"
TEXT = ''
while 1:
line = sys.stdin.readline()
if not line:
break
TEXT = TEXT + line
# Prepare actual message
message = """
From: %s
To: %s
Subject: %s
%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
# Send the mail
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
This script outputs :
Traceback (most recent call last):
File "/Users/christianlaustsen/Dropbox/Apps - Python/mail/smtplib_mail.py", line 32, in <module>
server = smtplib.SMTP(SERVER)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 239, in __init__
(code, msg) = self.connect(host, port)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 295, in connect
self.sock = self._get_socket(host, port, self.timeout)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 273, in _get_socket
return socket.create_connection((port, host), timeout)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 512, in create_connection
raise error, msg
error: [Errno 61] Connection refused
So as you can see, the connection is being refused. I’m running Python 2.6 on Mac OS X Snow Leopard (if that’s relevant).
I have tried searching around a lot, but haven’t been able to find a solution. Any help will be appreciated.
Answers:
My guess is that you do not have any SMTP server installed on your local machine.
If your emails are not sensitive, open a Gmail account and send your emails using it with Python.
Start a simple SMTP server with Python like so:
python -m smtpd -n -c DebuggingServer localhost:1025
If you start a local server as follows:
python -m smtpd -n -c DebuggingServer localhost:1025
Make sure to modify the mail-sending code to use the non-standard port number:
server = smtplib.SMTP(SERVER, 1025)
server.sendmail(FROM, TO, message)
server.quit()
If you don’t want to run a separate server, and if you’re only using Unix, you can use this technique, copied from http://www.yak.net/fqa/84.html, and originally from the Python FAQ:
On Unix, it’s very simple, using sendmail. The location of the sendmail program varies between systems; sometimes it is /usr/lib/sendmail, sometime /usr/sbin/sendmail. The sendmail manual page will help you out. Here’s some sample code:
SENDMAIL = "/usr/sbin/sendmail" # sendmail location
import os
p = os.popen("%s -t" % SENDMAIL, "w")
p.write("To: [email protected]")
p.write("Subject: testn")
p.write("n") # blank line separating headers from body
p.write("Some textn")
p.write("some more textn")
sts = p.close()
if sts != 0:
print "Sendmail exit status", sts
If you are root on your system then you may want to install opensmtpd. First this way you don’t need to run the server manually (this service is enabled by default so after smtpd installation either start it manually or reboot your machine). Second, you don’t need to change the line server = smtplib.SMTP(SERVER). To conclude, use yum install opensmtpd or the equivalent apt-get command.
For whatever reason, I had difficulty passing server and port to the constructor, but not the connect function. This ended up working for me:
s = smtplib.SMTP(timeout=30) #seconds
s.connect(EMAIL_HOST, EMAIL_PORT)
m = MIMEText('see subject')
m['subject'] = 'sweet subject'
m['from'] = EMAIL_FROM
m['to'] = to_list # comma-separated list of emails
s.sendmail(m['from'], m['to'].split(','), m.as_string())
s.quit()
I wanted to create something so that you could just copy paste it and have it work but this is the closest I got:
from email.message import EmailMessage
import smtplib
import os
def send_email(message,destination):
# important, you need to send it to a server that knows how to send e-mails for you
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
# don't know how to do it without cleartexting the password and not relying on some json file that you dont git control...
server.login('[email protected]', 'password_for_gmail')
msg = EmailMessage()
msg.set_content(message)
msg['Subject'] = 'TEST'
msg['From'] = '[email protected]'
msg['To'] = destination
server.send_message(msg)
if __name__ == '__main__':
send_email('msg','destination@email')
I feel the tutorial is misleading because it assumes without telling you very well that you already have a running server that sends e-mails for you…its odd. The only issue with my script is that I dont know how to make it work without having the cleartext password just written there but alas…at least it sends it? Just make a fake e-mail address or something…
made this question long time ago, so I don’t remember what this means exactly put will put it here just in case:
It works only if you enable access for less secure apps: myaccount.google.com/lesssecureapps . I think you should put that in answer.
I probably went around it by using a fake email only for that or somehting like that or an email from my org can’t remember. Good luck!
I’ve been trying to get my application to mail some outputted text to an email. For simplification I have isolated the script :
import smtplib
import sys
import os
SERVER = "localhost"
FROM = os.getlogin()
TO = [raw_input("To : ")]
SUBJECT = "Message From " + os.getlogin()
print "Message : (End with ^D)"
TEXT = ''
while 1:
line = sys.stdin.readline()
if not line:
break
TEXT = TEXT + line
# Prepare actual message
message = """
From: %s
To: %s
Subject: %s
%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
# Send the mail
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
This script outputs :
Traceback (most recent call last):
File "/Users/christianlaustsen/Dropbox/Apps - Python/mail/smtplib_mail.py", line 32, in <module>
server = smtplib.SMTP(SERVER)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 239, in __init__
(code, msg) = self.connect(host, port)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 295, in connect
self.sock = self._get_socket(host, port, self.timeout)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 273, in _get_socket
return socket.create_connection((port, host), timeout)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 512, in create_connection
raise error, msg
error: [Errno 61] Connection refused
So as you can see, the connection is being refused. I’m running Python 2.6 on Mac OS X Snow Leopard (if that’s relevant).
I have tried searching around a lot, but haven’t been able to find a solution. Any help will be appreciated.
My guess is that you do not have any SMTP server installed on your local machine.
If your emails are not sensitive, open a Gmail account and send your emails using it with Python.
Start a simple SMTP server with Python like so:
python -m smtpd -n -c DebuggingServer localhost:1025
If you start a local server as follows:
python -m smtpd -n -c DebuggingServer localhost:1025
Make sure to modify the mail-sending code to use the non-standard port number:
server = smtplib.SMTP(SERVER, 1025)
server.sendmail(FROM, TO, message)
server.quit()
If you don’t want to run a separate server, and if you’re only using Unix, you can use this technique, copied from http://www.yak.net/fqa/84.html, and originally from the Python FAQ:
On Unix, it’s very simple, using sendmail. The location of the sendmail program varies between systems; sometimes it is /usr/lib/sendmail, sometime /usr/sbin/sendmail. The sendmail manual page will help you out. Here’s some sample code:
SENDMAIL = "/usr/sbin/sendmail" # sendmail location
import os
p = os.popen("%s -t" % SENDMAIL, "w")
p.write("To: [email protected]")
p.write("Subject: testn")
p.write("n") # blank line separating headers from body
p.write("Some textn")
p.write("some more textn")
sts = p.close()
if sts != 0:
print "Sendmail exit status", sts
If you are root on your system then you may want to install opensmtpd. First this way you don’t need to run the server manually (this service is enabled by default so after smtpd installation either start it manually or reboot your machine). Second, you don’t need to change the line server = smtplib.SMTP(SERVER). To conclude, use yum install opensmtpd or the equivalent apt-get command.
For whatever reason, I had difficulty passing server and port to the constructor, but not the connect function. This ended up working for me:
s = smtplib.SMTP(timeout=30) #seconds
s.connect(EMAIL_HOST, EMAIL_PORT)
m = MIMEText('see subject')
m['subject'] = 'sweet subject'
m['from'] = EMAIL_FROM
m['to'] = to_list # comma-separated list of emails
s.sendmail(m['from'], m['to'].split(','), m.as_string())
s.quit()
I wanted to create something so that you could just copy paste it and have it work but this is the closest I got:
from email.message import EmailMessage
import smtplib
import os
def send_email(message,destination):
# important, you need to send it to a server that knows how to send e-mails for you
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
# don't know how to do it without cleartexting the password and not relying on some json file that you dont git control...
server.login('[email protected]', 'password_for_gmail')
msg = EmailMessage()
msg.set_content(message)
msg['Subject'] = 'TEST'
msg['From'] = '[email protected]'
msg['To'] = destination
server.send_message(msg)
if __name__ == '__main__':
send_email('msg','destination@email')
I feel the tutorial is misleading because it assumes without telling you very well that you already have a running server that sends e-mails for you…its odd. The only issue with my script is that I dont know how to make it work without having the cleartext password just written there but alas…at least it sends it? Just make a fake e-mail address or something…
made this question long time ago, so I don’t remember what this means exactly put will put it here just in case:
It works only if you enable access for less secure apps: myaccount.google.com/lesssecureapps . I think you should put that in answer.
I probably went around it by using a fake email only for that or somehting like that or an email from my org can’t remember. Good luck!