How to increment letters in Python?
Question:
Write a program that takes a character as input (a string of length 1), which you should assume is an upper-case character; the output should be the next character in the alphabet. If the input is ‘Z’, your output should be ‘A’. (You will need to use an if statement.)
So far I’ve tried several codes like this:
chr = input()
if chr == '65':
x = chr(ord(chr) + 1)
print(chr(65) + 1)
It says it prints with no output, just unsure how to get to the the right output. Im very new to programming.
Answers:
The below method is using ascii_letters.
import string
// returns a string of all the alphabets
// abcdefghijklmnopqrstuvwxyz"
result = string.ascii_letters
// get the index of the input alphabet and return the next alphabet in the results string.
// using the modulus to make sure when 'Z' is given as the input it returns to the first alphabet.
result[(result.index(alphabet.lower()) + 1) % 26].upper()
Hope this is what you are looking for
_chr = input('Enter character(A-Z): ')
if _chr == 'Z':
print('A')
else:
print(chr(ord(_chr) + 1))
This should work:
my_chr = ord(input())
if my_chr == 90:
print('A')
else:
print(chr(my_chr+1))
It takes the input letter (A-Z
) and gets its ord()
value. It then checks to see if the value is equal to Z
(ord('Z') == 90
) and prints A
otherwise, it increments it by 1 then turns it back to a string and prints it.
You can use the following idea:
A = 65
Z = 90
If you subtract ord(‘A’) from the input, you reduce the range to [0, 25]
So, you need to define the output inside the range [0, 25]. To avoid getting out this range, you should use ‘%’.
char_input = input()
return chr((ord(char_input) - ord('A') + 1) % 26 + ord('A'))
it means that, giving the input, you will subtract the value of ord(‘A’) to “fix” the range and, after that, add + 1. You will take % 26 to avoid getting out the range. After all of that, add ord(‘A’) again.
alpha=input()
if alpha =='Z': print('A')
else:print(chr(ord(alpha)+1))
“You will need to use an if statement”
We can increment character in many ways –
Method 1: Using ascii_lowercase –
import string
ch = input("Enter a character")
alphabets = string.ascii_lowercase
chIndex = alphabets.index(ch)
nextCh = alphabets[(chIndex + 1) % 26]
print(nextCh)
Method 2: Using ord() and chr() –
ch = input("Enter a character")
nextCh = ((ord(ch) - 96) % 26) + 97
print(chr(nextCh))
There are many other ways in which we can increment a character in Lowercase or Uppercase both –
Write a program that takes a character as input (a string of length 1), which you should assume is an upper-case character; the output should be the next character in the alphabet. If the input is ‘Z’, your output should be ‘A’. (You will need to use an if statement.)
So far I’ve tried several codes like this:
chr = input()
if chr == '65':
x = chr(ord(chr) + 1)
print(chr(65) + 1)
It says it prints with no output, just unsure how to get to the the right output. Im very new to programming.
The below method is using ascii_letters.
import string
// returns a string of all the alphabets
// abcdefghijklmnopqrstuvwxyz"
result = string.ascii_letters
// get the index of the input alphabet and return the next alphabet in the results string.
// using the modulus to make sure when 'Z' is given as the input it returns to the first alphabet.
result[(result.index(alphabet.lower()) + 1) % 26].upper()
Hope this is what you are looking for
_chr = input('Enter character(A-Z): ')
if _chr == 'Z':
print('A')
else:
print(chr(ord(_chr) + 1))
This should work:
my_chr = ord(input())
if my_chr == 90:
print('A')
else:
print(chr(my_chr+1))
It takes the input letter (A-Z
) and gets its ord()
value. It then checks to see if the value is equal to Z
(ord('Z') == 90
) and prints A
otherwise, it increments it by 1 then turns it back to a string and prints it.
You can use the following idea:
A = 65
Z = 90
If you subtract ord(‘A’) from the input, you reduce the range to [0, 25]
So, you need to define the output inside the range [0, 25]. To avoid getting out this range, you should use ‘%’.
char_input = input()
return chr((ord(char_input) - ord('A') + 1) % 26 + ord('A'))
it means that, giving the input, you will subtract the value of ord(‘A’) to “fix” the range and, after that, add + 1. You will take % 26 to avoid getting out the range. After all of that, add ord(‘A’) again.
alpha=input()
if alpha =='Z': print('A')
else:print(chr(ord(alpha)+1))
“You will need to use an if statement”
We can increment character in many ways –
Method 1: Using ascii_lowercase –
import string
ch = input("Enter a character")
alphabets = string.ascii_lowercase
chIndex = alphabets.index(ch)
nextCh = alphabets[(chIndex + 1) % 26]
print(nextCh)
Method 2: Using ord() and chr() –
ch = input("Enter a character")
nextCh = ((ord(ch) - 96) % 26) + 97
print(chr(nextCh))
There are many other ways in which we can increment a character in Lowercase or Uppercase both –