Python TypeError: 'set' object is not subscriptable
Question:
def create(ids):
policy = {
'Statement': []
}
for i in range(0, len(ids), 200):
policy['Statement'].append({
'Principal': {
'AWS': list(map(lambda id: f"arn:aws:iam::{id}:root", ids[i:i + 200]))
}
})
return policy
when I make a function call to this method create({'1','2'}) I get an TypeError: 'set' object is not subscriptable error on line
'AWS': list(map(lambda id: f"arn:aws:iam::{id}:root", ids[i:i + 200])).
Coming from a java background, is this somehow related to typecasting?
Does the error mean that I’m passing a set data structure to a list function?
How could can this be resovled?
Answers:
As per the Python’s Official Documentation, set data structure is referred as Unordered Collections of Unique Elements and that doesn’t support operations like indexing or slicing etc.
Like other collections, sets support x in set, len(set), and for x in set. Being an unordered collection, sets do not record element position or order of insertion. Accordingly, sets do not support indexing, slicing, or other sequence-like behavior.
When you define temp_set = {1, 2, 3} it just implies that temp_set contains 3 elements but there’s no index that can be obtained
>>> temp_set = {1,2,3}
>>> 1 in temp_set
>>> True
>>> temp_set[0]
>>> Traceback (most recent call last):
File "/usr/local/lib/python3.7/site-packages/IPython/core/interactiveshell.py", line 3326, in run_code
exec(code_obj, self.user_global_ns, self.user_ns)
File "<ipython-input-10-50885e8b29cf>", line 1, in <module>
temp_set[0]
TypeError: 'set' object is not subscriptable
Like @Carcigenicate says in the comment, sets cannot be indexed due to its unordered nature in Python. Instead, you can use itertools.islice in a while loop to get 200 items at a time from the iterator created from the given set:
from itertools import islice
def create(ids):
policy = {
'Statement': []
}
i = iter(ids)
while True:
chunk = list(islice(i, 200))
if not chunk:
break
policy['Statement'].append({
'Principal': {
'AWS': list(map(lambda id: f"arn:aws:iam::{id}:root", chunk))
}
})
return policy
I faced the same problem when dealing with list in python
In python list is defined with square brackets and not curly brackets
wrong List {1,2,3}
Right List [1,2,3]
This link elaborates more about list
https://www.w3schools.com/python/python_lists.asp
You may have installed an older version of python (3.6 or older) back when the dictionary data type was NOT ordered in nature (it was unordered in python v3.6 or earlier).
So install Python 3.7 or a newer version and you won’t face an error.
I ran your code on w3 and it works fine. 🙂
If you are lazy:
bob = ["a", "b", "b"]
bob = set(bob)
bob = list(bob)
Then you can deal with it.
def create(ids):
policy = {
'Statement': []
}
for i in range(0, len(ids), 200):
policy['Statement'].append({
'Principal': {
'AWS': list(map(lambda id: f"arn:aws:iam::{id}:root", ids[i:i + 200]))
}
})
return policy
when I make a function call to this method create({'1','2'}) I get an TypeError: 'set' object is not subscriptable error on line
'AWS': list(map(lambda id: f"arn:aws:iam::{id}:root", ids[i:i + 200])).
Coming from a java background, is this somehow related to typecasting?
Does the error mean that I’m passing a set data structure to a list function?
How could can this be resovled?
As per the Python’s Official Documentation, set data structure is referred as Unordered Collections of Unique Elements and that doesn’t support operations like indexing or slicing etc.
Like other collections, sets support x in set, len(set), and for x in set. Being an unordered collection, sets do not record element position or order of insertion. Accordingly, sets do not support indexing, slicing, or other sequence-like behavior.
When you define temp_set = {1, 2, 3} it just implies that temp_set contains 3 elements but there’s no index that can be obtained
>>> temp_set = {1,2,3}
>>> 1 in temp_set
>>> True
>>> temp_set[0]
>>> Traceback (most recent call last):
File "/usr/local/lib/python3.7/site-packages/IPython/core/interactiveshell.py", line 3326, in run_code
exec(code_obj, self.user_global_ns, self.user_ns)
File "<ipython-input-10-50885e8b29cf>", line 1, in <module>
temp_set[0]
TypeError: 'set' object is not subscriptable
Like @Carcigenicate says in the comment, sets cannot be indexed due to its unordered nature in Python. Instead, you can use itertools.islice in a while loop to get 200 items at a time from the iterator created from the given set:
from itertools import islice
def create(ids):
policy = {
'Statement': []
}
i = iter(ids)
while True:
chunk = list(islice(i, 200))
if not chunk:
break
policy['Statement'].append({
'Principal': {
'AWS': list(map(lambda id: f"arn:aws:iam::{id}:root", chunk))
}
})
return policy
I faced the same problem when dealing with list in python
In python list is defined with square brackets and not curly brackets
wrong List {1,2,3}
Right List [1,2,3]
This link elaborates more about list
https://www.w3schools.com/python/python_lists.asp
You may have installed an older version of python (3.6 or older) back when the dictionary data type was NOT ordered in nature (it was unordered in python v3.6 or earlier).
So install Python 3.7 or a newer version and you won’t face an error.
I ran your code on w3 and it works fine. 🙂
If you are lazy:
bob = ["a", "b", "b"]
bob = set(bob)
bob = list(bob)
Then you can deal with it.