Area of triangle using 3 sets of coordinates

Question

I am doing one question where i need to find area of triangle with given 3 sets of coordinates

So what will be the logic to convert array to pair in (a1,b1) (a2,b2) (a3,b3) and how to find area of triangle using this vertices

Here is my code

def getTriangleArea(x, y):

///What will be the code 


if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    x_count = int(input().strip())

    x = []

    for _ in range(x_count):
        x_item = int(input().strip())
        x.append(x_item)

    y_count = int(input().strip())

    y = []

    for _ in range(y_count):
        y_item = int(input().strip())
        y.append(y_item)

    result = getTriangleArea(x, y)

    fptr.write(str(result) + 'n')

    fptr.close()

Asked By: tyler

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Source

Answer 1

Assuming that you have the coordinates of your 3 input points as:

x1, y1
x2, y2
x3, y3

You can use Pythagorean theorem to find the lengths of all sides:

l1 = sqrt((x1 - x2)**2 + (y1 - y2)**2)
l2 = sqrt((x2 - x3)**2 + (y2 - y3)**2)
l3 = sqrt((x3 - x1)**2 + (y3 - y1)**2)

and then use Heron’s Formula for the area of the triangle:

p = (l1 + l2 + l3)/2
area = sqrt(p * (p - l1) * (p - l2) * (p - l3))

Answered By: ECLIPSE-MAN

Answer 2

Area of a triangle where (x1,y1) is 1st co-ordinate, (x2,y2) is 2nd co-ordinate, (x3,y3) is 3rd co-ordinate.

Area = 1/2[x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]

x = [2, 3, 7]
y = [4, -6, 8]


def get_area(x, y):
    area = 0.5 * (x[0] * (y[1] - y[2]) + x[1] * (y[2] - y[0]) + x[2]
                  * (y[0] - y[1]))
    return int(area)


coords = zip(x, y)
print('Area of points {}, {}, {} is {}'.format(*coords, get_area(x, y)))

output

Area of points (2, 4), (3, -6), (7, 8) is 27

Answered By: Ch3steR

Area of triangle using 3 sets of coordinates

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