python re.sub group: number after number
Question:
How can I replace foobar with foo123bar?
This doesn’t work:
>>> re.sub(r'(foo)', r'1123', 'foobar')
'J3bar'
This works:
>>> re.sub(r'(foo)', r'1hi', 'foobar')
'foohibar'
I think it’s a common issue when having something like number. Can anyone give me a hint on how to handle this?
Answers:
The answer is:
re.sub(r'(foo)', r'g<1>123', 'foobar')
Relevant excerpt from the docs:
In addition to character escapes and
backreferences as described above,
g will use the substring
matched by the group named name, as
defined by the (?P…) syntax.
g uses the corresponding
group number; g<2> is therefore
equivalent to 2, but isn’t ambiguous
in a replacement such as g<2>0. 20
would be interpreted as a reference to
group 20, not a reference to group 2
followed by the literal character ‘0’.
The backreference g<0> substitutes in
the entire substring matched by the
RE.
How can I replace foobar with foo123bar?
This doesn’t work:
>>> re.sub(r'(foo)', r'1123', 'foobar')
'J3bar'
This works:
>>> re.sub(r'(foo)', r'1hi', 'foobar')
'foohibar'
I think it’s a common issue when having something like number. Can anyone give me a hint on how to handle this?
The answer is:
re.sub(r'(foo)', r'g<1>123', 'foobar')
Relevant excerpt from the docs:
In addition to character escapes and
backreferences as described above,
g will use the substring
matched by the group named name, as
defined by the (?P…) syntax.
g uses the corresponding
group number; g<2> is therefore
equivalent to 2, but isn’t ambiguous
in a replacement such as g<2>0. 20
would be interpreted as a reference to
group 20, not a reference to group 2
followed by the literal character ‘0’.
The backreference g<0> substitutes in
the entire substring matched by the
RE.