Platform-independent file paths?
Question:
How can I use a file inside my app folder in Python? Platform independent of course…
something similar to this:
#!/bin/sh
mypath=${0%/*}
LIBDIR=$mypath/modules
Answers:
__file__ contains the module’s location. Use the functions in os.path to extract the directory from it.
You can use os.path and its functions, which take care of OS-specific paths:
>>> import os
>>> os.path.join('app', 'subdir', 'dir', 'filename.foo')
'app/subdir/dir/filename.foo'
On Windows, it should print out with backslashes.
import os
os.path.join(os.path.curdir, 'file.name')
or
import os
os.path.join(os.path.dirname(__file__), 'file.name')
depending upon whether it’s a module (2) or a single script (1), and whether you’re invoking it from the same directory (1), or from a different one (2).
Edit
Looking at the “attempt” you have in your question, I’d guess that you’d want (1).
In Python 3.4+ you can use pathlib:
from pathlib import Path
libdir = Path(__file__).resolve().with_name('modules')
How it works: the __file__ attribute contains the pathname of the file from which the module was loaded. You use it to initialize a Path object , make the path absolute using the resolve() method and replace the final path component using the with_name() method.
Try this CLR-compliant way:
import os
AppDomain = type('', (object,), {'__init__': (lambda self: self.CurrentDomain = type('', (object,), {'__init__': (lambda self: self.BaseDirectory = os.path.split(__file__)[0])})())})()
Usage:
AppDomain.CurrentDomain.BaseDirectory
Inspired by System.AppDomain in .NET Framework and Core.
Do you know how it works? First off, it imports os. After that, it creates a variable called AppDomain which is set into an instance of a type where its constructor sets its own CurrentDomain to an instance of a type where its constructor sets its own BaseDirectory to the first element in the array returned by os.path.split with the value of __file__ (the module path) as a parameter.
How can I use a file inside my app folder in Python? Platform independent of course…
something similar to this:
#!/bin/sh
mypath=${0%/*}
LIBDIR=$mypath/modules
__file__ contains the module’s location. Use the functions in os.path to extract the directory from it.
You can use os.path and its functions, which take care of OS-specific paths:
>>> import os
>>> os.path.join('app', 'subdir', 'dir', 'filename.foo')
'app/subdir/dir/filename.foo'
On Windows, it should print out with backslashes.
import os
os.path.join(os.path.curdir, 'file.name')
or
import os
os.path.join(os.path.dirname(__file__), 'file.name')
depending upon whether it’s a module (2) or a single script (1), and whether you’re invoking it from the same directory (1), or from a different one (2).
Edit
Looking at the “attempt” you have in your question, I’d guess that you’d want (1).
In Python 3.4+ you can use pathlib:
from pathlib import Path
libdir = Path(__file__).resolve().with_name('modules')
How it works: the __file__ attribute contains the pathname of the file from which the module was loaded. You use it to initialize a Path object , make the path absolute using the resolve() method and replace the final path component using the with_name() method.
Try this CLR-compliant way:
import os
AppDomain = type('', (object,), {'__init__': (lambda self: self.CurrentDomain = type('', (object,), {'__init__': (lambda self: self.BaseDirectory = os.path.split(__file__)[0])})())})()
Usage:
AppDomain.CurrentDomain.BaseDirectory
Inspired by System.AppDomain in .NET Framework and Core.
Do you know how it works? First off, it imports os. After that, it creates a variable called AppDomain which is set into an instance of a type where its constructor sets its own CurrentDomain to an instance of a type where its constructor sets its own BaseDirectory to the first element in the array returned by os.path.split with the value of __file__ (the module path) as a parameter.