[Python]Check if any string in a list is contains any string in another list

Question

I am writing a script for google news.

I get a list of news title and would like to check the title contains any keywords in a list.

e.g.

newstitle =['Python is awesome', 'apple is tasty', 'Tom cruise has new movie']
tag = ['Python','Orange', 'android']

If any keywords in tag is in the newstitle, I want it to return True value.

I know how to do it with single tag using

any('Python' in x for x in newstitle)

But how to do it with multiple keywords?
A if loop is doable but it seems dumb.

Please help. Thanks in advance.

Asked By: Max Cheung

||

Source

Answer 1

The below code should achieve the required:

any(t in x for x in newstitle for t in tag)

From the docs:

A list comprehension consists of brackets containing an expression
followed by a for clause, then zero or more for or if clauses. The
result will be a new list resulting from evaluating the expression in
the context of the for and if clauses which follow it.

Answered By: rok

Answer 2

for each newstitle in the list iterate through tag list for tag values in newstitle.

newstitles = ['Python is awesome', 'apple is tasty', 'Tom cruise has new movie']
tags = ['Python', 'Orange', 'android']

for newstitle in newstitles:
   for tag in tags:
      if newstitle.find(tag) != -1:
           #Do your operation...

Answered By: Alex

Answer 3

With regex (regular expressions), you can also check each newstitle for tags with

import re
for newstitle in newstitles:
    re.search('|'.join(tags), newstitle)`

Answered By: Christabella Irwanto

[Python]Check if any string in a list is contains any string in another list

Question:

Answers: