partition string in python and get value of last segment after colon
Question:
I need to get the value after the last colon in this example 1234567
client:user:username:type:1234567
I don’t need anything else from the string just the last id value.
To split on the first occurrence instead, see Splitting on first occurrence.
Answers:
Use this:
"client:user:username:type:1234567".split(":")[-1]
foo = "client:user:username:type:1234567"
last = foo.split(':')[-1]
result = mystring.rpartition(':')[2]
If you string does not have any :, the result will contain the original string.
An alternative that is supposed to be a little bit slower is:
result = mystring.split(':')[-1]
You could also use pygrok.
from pygrok import Grok
text = "client:user:username:type:1234567"
pattern = """%{BASE10NUM:type}"""
grok = Grok(pattern)
print(grok.match(text))
returns
{'type': '1234567'}
I need to get the value after the last colon in this example 1234567
client:user:username:type:1234567
I don’t need anything else from the string just the last id value.
To split on the first occurrence instead, see Splitting on first occurrence.
Use this:
"client:user:username:type:1234567".split(":")[-1]
foo = "client:user:username:type:1234567"
last = foo.split(':')[-1]
result = mystring.rpartition(':')[2]
If you string does not have any :, the result will contain the original string.
An alternative that is supposed to be a little bit slower is:
result = mystring.split(':')[-1]
You could also use pygrok.
from pygrok import Grok
text = "client:user:username:type:1234567"
pattern = """%{BASE10NUM:type}"""
grok = Grok(pattern)
print(grok.match(text))
returns
{'type': '1234567'}