Function to return table of a number

Question

I have tried below code to return a multiplication table for input number:

def table_of(n):
    for i in range(1,11):
        print(n,"*",i,"=",n*i)
a = input("Enter a Number:")
table_of(a)

This returns:

Enter a Number:2
2 * 1 = 2
2 * 2 = 22
2 * 3 = 222
2 * 4 = 2222
2 * 5 = 22222
2 * 6 = 222222
2 * 7 = 2222222
2 * 8 = 22222222
2 * 9 = 222222222
2 * 10 = 2222222222

What is the problem?

Asked By: Shubh_K

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Source

Answer 1

The output from an input statement is always a string. You need to convert n to an integer before multiplying, either at the input statement, or in the print, as below.

def table_of(n):
    for i in range(1,11):
        print(n,"*",i,"=",int(n)*i)
a = input("Enter a Number:")
table_of(a)

Gives the output:

Enter a Number:>? 2
2 * 1 = 2
2 * 2 = 4
2 * 3 = 6
2 * 4 = 8
2 * 5 = 10
2 * 6 = 12
2 * 7 = 14
2 * 8 = 16
2 * 9 = 18
2 * 10 = 20

Answered By: David Buck

Answer 2

The input() function returns a string therefor the loop prints that string i times. The solution would be to replace a = input(“Enter a number: ”) with

a = int(input(“Enter a number: ”))

Answered By: user2840420

Answer 3

make a function to return a table of any number without using print inside a functio python

def table(x):
for i in range(1,11):
yield f'{x}{i}={xi}’
num = int(input("Enter a number : "))
a = table(num)
for i in a:
print(i)

Answered By: Kamal

Function to return table of a number

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