Python – how to convert and determine a type of a 5 digit date?

Question

I have some of the date fields represented as 5-digit numbers. And there is a mapping from the numbers to an actual date. However I can’t figure out what logic should be applied to convert the numbers to dates in the "%Y-%m-%d" format?

13581 -> 2007-03-09
12784 -> 2005-01-01

Asked By: samba

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Source

Answer 1

As shown by

import datetime
datetime.date(2005, 1, 1)-datetime.timedelta(days=12784)
# datetime.date(1970, 1, 1)

your number is the number of days since 1970-01-01.

So, you can get the date by:

datetime.date(1970, 1, 1) + datetime.timedelta(days=12784)
# datetime.date(2005, 1, 1)

Answered By: Thierry Lathuille

Answer 2

Here you go:

>>> from datetime import date, timedelta
>>> (date(1970,1,1) + timedelta(days=12784)).strftime("%Y-%m-%d")
'2005-01-01'

Answered By: Balaji Ambresh

Answer 3

The numbers shown are the numbers of days since 1st January 1970, which is the origin of Unix time.

They can be converted using for example:

from datetime import datetime, timedelta
n = 13581
print((datetime.utcfromtimestamp(0) + timedelta(n)).strftime("%Y-%m-%d"))

gives:

2007-03-09

Here timedelta is called with a single argument, being the offset in days. In general it is called with timedelta(days, seconds, microseconds) but all of these arguments default to zero.

Answered By: alani

Answer 4

Just in case for a column in dataframe while using the accepted answer, you can use .apply:

df["column"].apply(lambda x: (datetime.utcfromtimestamp(0) + timedelta(int(x))).strftime("%Y-%m-%d"))

Answered By: lulmeister

Python – how to convert and determine a type of a 5 digit date?

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