Given an array of ints length 3, figure out which is larger, the first or last element in the array, and set all the other elements to be that value

Question

Given an array of ints length 3, figure out which is larger, the first or last element in the array, and set all the other elements to be that value. Return the changed array

    def max_end3(nums):
       if nums[0:] > nums[:-1]:
       # this is where I am lost
    return print(nums)
       elif nums[:-1] > nums[0:]:
       # this is where I am lost
    return print(nums)  

    max_end3([1, 2, 3])
    max_end3([11, 5, 9])
    max_end3([2, 11, 3])

I am missing something and I cant seem to remember it. there is a +1 somewhere that allows me to iterate through each element and modify them as it goes. I cannot seem to remember how to assign the larger value to every item in the list.
Here is a link to the problem https://codingbat.com/prob/p135290

I appreciate any assistance.
Thank You.

Asked By: Mr. Mac

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Source

Answer 1

You can find the maximum value using in-built max and form a list of the maximum values:

def max_end3(nums):
    m = max(nums[0], nums[-1])
    print([m for _ in nums])

Answered By: Austin

Answer 2

You could do a list comprehension to change all the values, it would be something like

list = [value = list[:0] for value in list]

also the return statements aren’t indented

Answered By: user14019143

Answer 3

Check this out

def max_end3(nums):
  return 3 * [max(nums[0], nums[-1])]

Answered By: post_lupy

Given an array of ints length 3, figure out which is larger, the first or last element in the array, and set all the other elements to be that value

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