Is there a way I could code a cipher that doesn't incorporated a space in the cipher?

Question

I am coding a basic Caesar Cipher, which is almost finished, but has a small problem. When I run the code and it asks for the user’s input, if the inputs any spaces, the program will include them in the cipher. I want to just pass it without encrypting.

This is the code –

#This is a working code encrypter and decrypter
#Created by Aykhan Salimov on 08.23.2020
#"s" specifies the number of the shift to encrypt
s = 3
text = input("Input text that you wish to be ciphered: ")
def cipherText(text,s):
    global result
    result = ""
    x = len(text) - text.count(" ")
    
    for i in range(len(text)):
        char = text[i]
        if char.isupper():
            result += chr((ord(char) + s - 65) % 26 + 65)
        else:
            result += chr((ord(char) + s - 97) % 26 + 97)
    print("Ciphertext:", result)
#This is the decrypter
#"d" is the amount need to shift back
d = s * -1
#a is the variable used to use the encrypted code
def plainText(text,d,result):
    decrypt = ""
    for i in range(len(result)):
        char = result[i]
        if char.isupper():
            decrypt += chr((ord(char) + d - 65) % 26 + 65)
        else:
            decrypt += chr((ord(char) + d - 97) % 26 + 97)
    print("Plaintext:", decrypt)
cipherText(text,s)
plainText(text,d,result)

This program does exactly what I want it to, but it isn’t correctly able to exclude spaces from the cipher. I am a beginner programmer, and I really need help on creating my first cipher.

Asked By: Aykhan

||

Source

Answer 1

if what you want is to just pass it without encrypting it you can do the following

for i in range(len(text)):
        char = text[i]
        if char == " ":
            result += " "
            continue
        if char.isupper():
            result += chr((ord(char) + s - 65) % 26 + 65)
        else:
            result += chr((ord(char) + s - 97) % 26 + 97)

or if what you want is to completely remove it you can do result += "".

Answered By: EHM

Answer 2

If you want to remove spaces from input, You can use replace():

string = string.replace(" ","") #Replace space

Input:

Hi Aykhan

Output:

HiAykhan

Answered By: Mehdi Mostafavi

Answer 3

Fixed your code:

We handle each of the three cases:

Uppercase
Lowercase
Non-letters, such as spaces

What was the problem?

Lowercase and non-letters were treated in the same condition of:

if char.isupper():
     <code>
# Here both space and lower-case were handeled
else:
    <code>

Example:

Input text that you wish to be ciphered: Sabich dsF
Ciphertext: Vaelfk gvI
Plaintext: Sabich dsF

# This is a working code encrypter and decrypter
# Created by Aykhan Salimov on 08.23.2020
# "s" specifies the number of the shift to encrypt
s = 3
text = input("Input text that you wish to be ciphered: ")


def cipherText(text, s):
    global result
    result = ""
    x = len(text) - text.count(" ")

    for i in range(len(text)):
        char = text[i]
        if 'a' < char < 'z':
            result += chr((ord(char) + s - 97) % 26 + 97)
        elif 'A' < char < 'Z':
            result += chr((ord(char) + s - 65) % 26 + 65)
        else:
            result += char
    print("Ciphertext:", result)


# This is the decrypter
# "d" is the amount need to shift back
d = s * -1


# a is the variable used to use the encrypted code
def plainText(text, d, result):
    decrypt = ""
    for i in range(len(result)):
        char = result[i]
        if 'a' < char < 'z':
            decrypt += chr((ord(char) + d - 97) % 26 + 97)
        elif 'A' < char < 'Z':
            decrypt += chr((ord(char) + d - 65) % 26 + 65)
        else:
            decrypt += char
    print("Plaintext:", decrypt)


cipherText(text, s)
plainText(text, d, result)

Answered By: Aviv Yaniv

Is there a way I could code a cipher that doesn't incorporated a space in the cipher?

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