What is the best way to create a string array in python?

The simple answer is, “You don’t.” At the point where you need something to be of fixed length, you’re either stuck on old habits or writing for a very specific problem with its own unique set of constraints.

But what is a reason to use fixed size? There is no actual need in python to use fixed size arrays(lists) so you always have ability to increase it’s size using append, extend or decrease using pop, or at least you can use slicing.

x = [''  for x in xrange(10)]

In Python, the tendency is usually that one would use a non-fixed size list (that is to say items can be appended/removed to it dynamically). If you followed this, there would be no need to allocate a fixed-size collection ahead of time and fill it in with empty values. Rather, as you get or create strings, you simply add them to the list. When it comes time to remove values, you simply remove the appropriate value from the string. I would imagine you can probably use this technique for this. For example (in Python 2.x syntax):

>>> temp_list = []
>>> print temp_list
[]
>>> 
>>> temp_list.append("one")
>>> temp_list.append("two")
>>> print temp_list
['one', 'two']
>>> 
>>> temp_list.append("three")
>>> print temp_list
['one', 'two', 'three']
>>> 

Of course, some situations might call for something more specific. In your case, a good idea may be to use a deque. Check out the post here: Python, forcing a list to a fixed size. With this, you can create a deque which has a fixed size. If a new value is appended to the end, the first element (head of the deque) is removed and the new item is appended onto the deque. This may work for what you need, but I don’t believe this is considered the “norm” for Python.

Are you trying to do something like this?

>>> strs = [s.strip('()') for s in ['some\', '(list)', 'of', 'strings']]
>>> strs 
['some', 'list', 'of', 'strings']

The error message says it all: strs[sum-1] is a tuple, not a string. If you show more of your code someone will probably be able to help you. Without that we can only guess.

Sometimes I need a empty char array. You cannot do “np.empty(size)” because error will be reported if you fill in char later. Then I usually do something quite clumsy but it is still one way to do it:

# Suppose you want a size N char array
charlist = [' ']*N # other preset character is fine as well, like 'x'
chararray = np.array(charlist)
# Then you change the content of the array
chararray[somecondition1] = 'a'
chararray[somecondition2] = 'b'

The bad part of this is that your array has default values (if you forget to change them).

The best and most convenient method for creating a string array in python is with the help of NumPy library.

Example:

import numpy as np
arr = np.chararray((rows, columns))

This will create an array having all the entries as empty strings. You can then initialize the array using either indexing or slicing.

def _remove_regex(input_text, regex_pattern):
    findregs = re.finditer(regex_pattern, input_text) 
    for i in findregs: 
        input_text = re.sub(i.group().strip(), '', input_text)
    return input_text

regex_pattern = r"buntilb|bcanb|bboatb"
_remove_regex("row and row and row your boat until you can row no more", regex_pattern)

w means that it matches word characters, a|b means match either a or b, b represents a word boundary

If you want to take input from user here is the code

If each string is given in new line:

strs = [input() for i in range(size)]

If the strings are separated by spaces:

strs = list(input().split())

strlist =[{}]*10
strlist[0] = set()
strlist[0].add("Beef")
strlist[0].add("Fish")
strlist[1] = {"Apple", "Banana"}
strlist[1].add("Cherry")
print(strlist[0])
print(strlist[1])
print(strlist[2])
print("Array size:", len(strlist))
print(strlist)