ValueError: invalid literal for int() with base 10: '2 3 6 6 5'

Question

While solving a problem on Hackerrank, i am getting this error –

Traceback (most recent call last):
  File "Solution.py", line 6, in <module>
    x = int(input())
ValueError: invalid literal for int() with base 10: '2 3 6 6 5'

Here is the code i have written to get the runner-up score in an array of scores –

        from array import *
        n = int(input())
        A = array('i', [])
        
        for a in range(n):
            x = int(input())
            A.append(int(x))
        
        for i in range(0, len(A)):
            for j in range(i+1, len(A)):
                if A[i] > A[j]:
                    temp = A[i]
                    A[i] = A[j]
                    A[j] = temp
        print(A[len(A)-2])

Funny thing is, it works in PyCharm but not in HackerRank.

Asked By: striker00

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Source

Answer 1

You should really post a reproducible example, because merely stating that the code is run on Hackerrank is not sufficient to reproduce the problem.

However, it appears that your code is being called with an input of '2 3 6 6 5', and if you want to append all of these numbers to the list, then you would need to change:

            x = int(input())
            A.append(int(x))

to:

            for x in input().split():
                A.append(int(x))

Your existing code will fail if the input is a string containing a space-separated list of integers. And where the input string contains just the one integer, it is unnecessarily converting it to int twice (the second call to int will simply return the value which is already an int).

Answered By: alani

Answer 2

l =[]
n = int(input())
for x in input().split():
    l.append(int(x))
m=max(l)
while max(l)==m:
    l.remove(m)
print(max(l))

Answered By: suhas gogi

ValueError: invalid literal for int() with base 10: '2 3 6 6 5'

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