Extracting gps coordinates from image using Python

Question

from PIL import Image
from PIL.ExifTags import TAGS

# path to the image or video
imagename = "image.jpg"

# read the image data using PIL
image = Image.open(imagename)

# extract EXIF data
exifdata = image.getexif()

# iterating over all EXIF data fields
for tag_id in exifdata:
    # get the tag name, instead of human unreadable tag id
    tag = TAGS.get(tag_id, tag_id)
    data = exifdata.get(tag_id)
    # decode bytes 
    if isinstance(data, bytes):
        data = data.decode()
    print(f"{tag:25}: {data}")

ExifVersion : 0220
ComponentsConfiguration :
ShutterSpeedValue : (1345, 100)
DateTimeOriginal : 2020:08:27 09:43:15
DateTimeDigitized : 2020:08:27 09:43:15
ApertureValue : (185, 100)
BrightnessValue : (930, 100)
ExposureBiasValue : (0, 10)
MaxApertureValue : (185, 100)
MeteringMode : 2
Flash : 0
FocalLength : (358, 100)
UserComment :
ColorSpace : 1
ExifImageWidth : 4128
SceneCaptureType : 0
SubsecTime : 0424
SubsecTimeOriginal : 0424
SubsecTimeDigitized : 0424
ExifImageHeight : 1908
ImageLength : 1908
Make : samsung
Model : SM-M305F
Orientation : 6
YCbCrPositioning : 1
ExposureTime : (1, 2786)
ExifInteroperabilityOffset: 944
XResolution : (72, 1)
FNumber : (190, 100)
SceneType :
YResolution : (72, 1)
ImageUniqueID : E13LLLI00PM E13LLMK03PA

ExposureProgram : 2
CustomRendered : 0
ISOSpeedRatings : 40
ResolutionUnit : 2
ExposureMode : 0
FlashPixVersion : 0100
ImageWidth : 4128
WhiteBalance : 0
Software : M305FDDU5CTF2
DateTime : 2020:08:27 09:43:15
DigitalZoomRatio : (0, 0)
FocalLengthIn35mmFilm : 27
Contrast : 0
Saturation : 0
Sharpness : 0
ExifOffset : 226
MakerNote : 0100 Z@P

Asked By: srini

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Source

Answer 1

Using the module piexif (pip install piexif) you can get to the GPS information in the exif as follows.

from pprint import pprint
from PIL import Image
import piexif

codec = 'ISO-8859-1'  # or latin-1

def exif_to_tag(exif_dict):
    exif_tag_dict = {}
    thumbnail = exif_dict.pop('thumbnail')
    exif_tag_dict['thumbnail'] = thumbnail.decode(codec)

    for ifd in exif_dict:
        exif_tag_dict[ifd] = {}
        for tag in exif_dict[ifd]:
            try:
                element = exif_dict[ifd][tag].decode(codec)

            except AttributeError:
                element = exif_dict[ifd][tag]

            exif_tag_dict[ifd][piexif.TAGS[ifd][tag]["name"]] = element

    return exif_tag_dict

def main():
    filename = 'IMG_2685.jpg'  # obviously one of your own pictures
    im = Image.open(filename)

    exif_dict = piexif.load(im.info.get('exif'))
    exif_dict = exif_to_tag(exif_dict)

    pprint(exif_dict['GPS'])

if __name__ == '__main__':
   main()

result

{'GPSAltitude': (94549, 14993),
 'GPSAltitudeRef': 0,
 'GPSDateStamp': '2020:09:04',
 'GPSDestBearing': (1061399, 5644),
 'GPSDestBearingRef': 'T',
 'GPSHPositioningError': (5, 1),
 'GPSImgDirection': (1061399, 5644),
 'GPSImgDirectionRef': 'T',
 'GPSLatitude': ((12, 1), (34, 1), (1816, 100)),
 'GPSLatitudeRef': 'N',
 'GPSLongitude': ((99, 1), (57, 1), (4108, 100)),
 'GPSLongitudeRef': 'E',
 'GPSSpeed': (0, 1),
 'GPSSpeedRef': 'K',
 'GPSTimeStamp': ((13, 1), (2, 1), (4599, 100)),
 'GPSVersionID': (2, 2, 0, 0)}

Here exif_to_tag translates exif codes to more readable tags.

Answered By: Bruno Vermeulen

Answer 2

Using this module you can get the information.

pip install exif

Use this code then!

from exif import Image

def decimal_coords(coords, ref):
    decimal_degrees = coords[0] + coords[1] / 60 + coords[2] / 3600
    if ref == "S" or ref =='W' :
        decimal_degrees = -decimal_degrees
    return decimal_degrees

def image_coordinates(image_path):

    with open(image_path, 'rb') as src:
        img = Image(src)
    if img.has_exif:
        try:
            img.gps_longitude
            coords = (decimal_coords(img.gps_latitude,
                      img.gps_latitude_ref),
                      decimal_coords(img.gps_longitude,
                      img.gps_longitude_ref))
        except AttributeError:
            print ('No Coordinates')
    else:
        print ('The Image has no EXIF information')
        
    return({"imageTakenTime":img.datetime_original, "geolocation_lat":coords[0],"geolocation_lng":coords[1]})

image_coordinates('Your image path')

result

{'imageTakenTime': '2012:04:22 16:51:08',
 'geolocation_lat': 52.314166666666665,
 'geolocation_lng': 4.941}

Answered By: gamingflexer

Extracting gps coordinates from image using Python

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