Seaborn title error – AttributeError: 'FacetGrid' object has no attribute 'set_title

Question

I created a lineplot graph to begin with using the following code:

plot = sns.lineplot(data=tips,
             x="sex",
             y="tip",
             ci=50,
             hue="day",
             palette="Accent")
plot.set_title("Value of Tips Given to Waiters, by Days of the Week and Sex", fontsize=24, pad=30, fontdict={"weight": "bold"})
plot.legend("")

I have realised that its actually a catplot chart that I need so I amended the code to the following:

plot = sns.catplot (data=tips,
             x="day",
             y="tip",
             kind='bar',
             ci=50,
             hue="sex",
             palette="Accent")
plot.set_title("Value of Tips Given to Waiters, by Days of the Week and Sex", fontsize=24, pad=30, fontdict={"weight": "bold"})
plot.legend("")

However I am getting the following error message with the title: ‘AttributeError: ‘FacetGrid’ object has no attribute ‘set_title”.

Why is my title not working for the catplot chart?

Asked By: DSouthy

||

Source

Answer 1

When you call catplot, it returns a FacetGrid object, so to change the the title and remove legend, you have to use the legend= option inside the function, and also use plot.fig.suptitle() :

import seaborn as sns
tips = sns.load_dataset("tips")
plot = sns.catplot (data=tips,
             x="day",
             y="tip",
             kind='bar',
             ci=50,
             hue="sex",
             palette="Accent", legend=False)

plot.fig.suptitle("Value of Tips Given to Waiters, by Days of the Week and Sex",
                  fontsize=24, fontdict={"weight": "bold"})

Answered By: StupidWolf

Answer 2

Same answer as @StupidWolf, but with additional adjustment for title position:

import seaborn as sns
tips = sns.load_dataset("tips")
plot = sns.catplot (data=tips,
             x="day",
             y="tip",
             kind='bar',
             ci=50,
             hue="sex",
             palette="Accent", legend=False);
plot.figure.subplots_adjust(top=0.8);
plot.figure.suptitle(
    "Value of Tips Given to Waiters, by Days of the Week and Sex",
    fontsize=24,
    fontdict={"weight": "bold"}
);

Answered By: ling

Seaborn title error – AttributeError: 'FacetGrid' object has no attribute 'set_title

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