How to use loc[] In python

Question

For the following dataframe:

d = {'a':[10,11,12,13],'b':[20,21,22,23], 'c':[30,31,32,33]}
pd_df = pd.DataFrame(d)
pd_df.set_index('a')

This code

pd_df.loc[10]

gives the following error:

~/.local/lib/python3.6/site-packages/pandas/core/indexing.py in _validate_key(self, key, axis)
   1789                 if not ax.contains(key):
-> 1790                     error()
   1791             except TypeError as e:

~/.local/lib/python3.6/site-packages/pandas/core/indexing.py in error()
   1784                                .format(key=key,
-> 1785                                        axis=self.obj._get_axis_name(axis)))
   1786 

KeyError: 'the label [10] is not in the [index]'

How can I fix it?

Asked By: Samrath Chadha

||

Source

Answer 1

If you want to set index to a, then do the following:

d = {'a':[10,11,12,13],'b':[20,21,22,23], 'c':[30,31,32,33]}
pd_df = pd.DataFrame(d)
pd_df = pd_df.set_index('a')  ## <<< CHANGE HERE

Then

pd_df.loc[10]

Output:

b    20
c    30
Name: 10, dtype: int64

Answered By: Ala Tarighati

Answer 2

I recommend to use iloc since you’re filtering by index.

Answered By: john johnson

How to use loc[] In python

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