How to find the odd numbers in a given range in Python?

Question

Shown below is the code to print the odd numbers in a given range of integers.

When I’m using the return keyword, it’s checking the 3 and returning the num, so the output is 3, but this is not the required output I’m looking for. The required output is 3,5.

In another case when I’m using the print function instead of return, the program checks 3,4,5 and returns ‘3 & 5’ as the output.

Could help me to get the right output

def oddNumbers(l, r):

    # iterating each number in list
    for num in range(l, r + 1):

        # checking condition
        if num % 2 != 0:

            return num

Asked By: pratap pudi

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Source

Answer 1

You can use the following approach which stores the interim values in a list named odd and returns the list after going through the range of numbers between l and r:

def oddNumbers(l, r):
    odd = []
    # iterating each number in list
    for num in range(l, r + 1):

        # checking condition
        if num % 2 != 0:
            odd.append(num)
    return odd

Answered By: sophros

Answer 2

There is no need to go through the range. Take a look at the first number: if it is odd, build a new range with the step of 2 that starts at that number. If it is even, then start at the next number.

def oddNumbers(l, r):
    if l % 2 == 1: 
        return list(range(l,     r + 1, 2))
    else: 
        return list(range(l + 1, r + 1, 2))

Or, in a more Pythonic way:

def oddNumbers(l, r):
    return list(range(l if l % 2 else l + 1, r + 1, 2))

Answered By: DYZ

Answer 3

Simple solution using list comprehension:

def odd(l,u):
    return([a for a in range(l,u) if a%2 != 0])

Answered By: ayesha ayub

How to find the odd numbers in a given range in Python?

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