LAB: Interstate highway numbers

Question

I have a assignment to write a program that takes a highway number as input and outputs whether the highway is primary or auxiliary, goes east/west, north/south, and if it is auxiliary, what primary highway is it serving. Here is my code:

highway_number = int(input(''))

if highway_number >= 1 and highway_number <= 99:
    prim = 'is primary,'
    if (highway_number % 2) == 0:
        print('I-', highway_number, prim, 'going east/west.')
    else:
        print('I-', highway_number, prim, 'going north/south.')
elif highway_number >= 100 and highway_number <= 999:
    aux = 'is auxiliary,'
    if (highway_number % 2) == 0:
        print('I-', highway_number, aux, 'serving I- %d, going east/west.' % (highway_number%100))
    else:
        print('I-', highway_number, aux, 'serving I- %d, going north/south.' % (highway_number%100))
else:
    print(highway_number, 'is not a valid interstate highway number.')

But if I run it. It adds a space between the "I-" and the highway number.

Asked By: Adam Dickenson

||

Source

Answer 1

Your issue is in the part where you print: Using print(string, string) your writing out 2 seperate stings, which per default by python will be seperated by a blank space. Your going to have to append the strings which can easily be done by a + print(string + string). BE sure to parse numbers etc first using str(toparse).

For the second part printing a space between I- and the number its because in your string you have a space I- %d. Yust change it to I-%d

Hope this helps 😀

In complete

highway_number = int(input(''))

if highway_number >= 1 and highway_number <= 99:
    prim = 'is primary,'
    if (highway_number % 2) == 0:
        print('I-' + str(highway_number), prim, 'going east/west.')
    else:
        print('I-' + str(highway_number), prim, 'going north/south.')
elif highway_number >= 100 and highway_number <= 999:
    aux = 'is auxiliary,'
    if (highway_number % 2) == 0:
        print('I-' + str(highway_number), aux, 'serving I-%d, going east/west.' % (highway_number%100))
    else:
        print('I-' + str(highway_number), aux, 'serving I-%d, going north/south.' % (highway_number%100))
else:
    print(highway_number, 'is not a valid interstate highway number.')

Answered By: Noah

Answer 2

try this

print('I-'+str(highway_number), prim, 'going east/west.')

and

print('I-'+ str(highway_number), aux, 'serving I-%d, going east/west.' % (highway_number%100))

Answered By: KingLarry

Answer 3

The question to this answer has changed by adding new requirements added new section to help others out that are looking for the same answers.

highway_number = int(input())

if highway_number >= 1 and highway_number <= 99:
    prim = "is primary,"
    if (highway_number % 2) == 0:
        print('I-' + str(highway_number), prim, 'going east/west.')
    else:
        print('I-' + str(highway_number), prim, 'going north/south.')
elif highway_number >= 100 and highway_number <= 999:
    aux = 'is auxiliary,'
    if highway_number % 100 == 0:
        print(highway_number, 'is not a valid interstate highway number.')
    elif (highway_number % 2) == 0:
        print('I-' + str(highway_number), aux, 'serving I-%d, going east/west.' % (highway_number%100))
    else:
        print('I-' + str(highway_number), aux, 'serving I-%d, going north/south.' % (highway_number%100))
else:
    print(highway_number, 'is not a valid interstate highway number.')

Answered By: ottodamus

LAB: Interstate highway numbers

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