Where are the ampersand and vertical bar characters used in Python?

Question

In the Wikipedia page describing short-circuit evaluation, & and | are listed as eager operators in Python. What does this mean and when are they used in the language?

Asked By: Yktula

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Answer 1

It means the left operand and the right operand are always evaluated. & is the bitwise AND operator and | is the bitwise OR operator.

Answered By: icktoofay

Answer 2

& —-> Used to AND bitwise i.e. bit by bit

similarly,

| —> used to OR bitwise

Whenevr you find any python problem, try to use python.org, its helpful

Answered By: Stuti

Answer 3

The wikipedia page is wrong, I’ve corrected it. | and & are not boolean operators, even though they are eager operators, which just means that they are not short circuit operators. As you probably know, here’s how the python and and or operators work:

>>> def talk(x):
...     print "Evaluating: ", bool(x)
...     return x
... 
>>> talk(1 == 1) or talk(2 == 1)   # 2 == 1 is not evaluated
Evaluating:  True
True
>>> talk(1 == 1) and talk(2 == 1)
Evaluating:  True
Evaluating:  False
False
>>> talk(1 == 2) and talk(1 == 3)  # 1 == 3 is not evaluated
Evaluating:  False
False

As far as I know, python has no eager boolean operators, they would have to be explicitly coded, for instance like this:

>>> def eager_or(a, b):
...    return a or b
...
>>> eager_or(talk(1 == 1), talk(2 == 1))
Evaluating:  True
Evaluating:  False
True

Now a and b are automatically evaluated when the function is called, even though or still short circuits.

As for the usage of | and &, when used with numbers, they are binary operators:

>>> bin(0b11110000 & 0b10101010)
'0b10100000'
>>> bin(0b11110000 | 0b10101010)
'0b11111010'

You’re most likely to use | this way with python bindings to libraries that uses flags, like wxWidgets:

>>> frame = wx.Frame(title="My Frame", style=wx.MAXIMIZE | wx.STAY_ON_TOP)
>>> bin(wx.MAXIMIZE)
'0b10000000000000'
>>> bin(wx.STAY_ON_TOP)
'0b1000000000000000'
>>> bin(wx.MAXIMIZE | wx.STAY_ON_TOP)
'0b1010000000000000'

When used with sets, they do the intersection and union operations, respectively:

>>> set("abcd") & set("cdef")
set(['c', 'd'])
>>> set("abcd") | set("cdef")
set(['a', 'c', 'b', 'e', 'd', 'f'])

Answered By: Lauritz V. Thaulow

Answer 4

Something missing from the other answers here is that & and | don’t have any universal meaning in Python; their meaning depends on the operands’ types, using the magic __and__ and __or__ methods. Since these are methods, the operands are both evaluated (i.e. without short-circuiting) before being passed as arguments.

On bool values they are logical “and” and logical “or”:

>>> True & False
False
>>> True | False
True
>>> bool.__and__(True, False)
False
>>> bool.__or__(True, False)
True

On int values they are bitwise “and” and bitwise “or”:

>>> bin(0b1100 & 0b1010)
'0b1000'
>>> bin(0b1100 | 0b1010)
'0b1110'
>>> bin(int.__and__(0b1100, 0b1010))
'0b1000'
>>> bin(int.__or__(0b1100, 0b1010))
'0b1110'

On sets, they are intersection and union:

>>> {1, 2} & {1, 3}
{1}
>>> {1, 2} | {1, 3}
{1, 2, 3}
>>> set.__and__({1, 2}, {1, 3})
{1}
>>> set.__or__({1, 2}, {1, 3})
{1, 2, 3}

A couple of extra notes:

The __and__ and __or__ methods are always looked up on the class, not on the instance. So if you assign obj.__and__ = lambda x, y: ... then it’s still obj.__class__.__and__ that’s invoked.
The __rand__ and __ror__ methods on the class will take priority, if they are defined.

See the Python language reference for more details.

Answered By: kaya3

Where are the ampersand and vertical bar characters used in Python?

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