python time + timedelta equivalent
Question:
I’m trying to do something like this:
time() + timedelta(hours=1)
however, Python doesn’t allow it, apparently for good reason.
Does anyone have a simple work around?
Related:
Answers:
Workaround:
t = time()
t2 = time(t.hour+1, t.minute, t.second, t.microsecond)
You can also omit the microseconds, if you don’t need that much precision.
This is a bit nasty, but:
from datetime import datetime, timedelta
now = datetime.now().time()
# Just use January the first, 2000
d1 = datetime(2000, 1, 1, now.hour, now.minute, now.second)
d2 = d1 + timedelta(hours=1, minutes=23)
print d2.time()
The solution is in the link that you provided in your question:
datetime.combine(date.today(), time()) + timedelta(hours=1)
Full example:
from datetime import date, datetime, time, timedelta
dt = datetime.combine(date.today(), time(23, 55)) + timedelta(minutes=30)
print dt.time()
Output:
00:25:00
If it’s worth adding another file / dependency to your project, I’ve just written a tiny little class that extends datetime.time with the ability to do arithmetic. If you go past midnight, it just wraps around:
>>> from nptime import nptime
>>> from datetime import timedelta
>>> afternoon = nptime(12, 24) + timedelta(days=1, minutes=36)
>>> afternoon
nptime(13, 0)
>>> str(afternoon)
'13:00:00'
It’s available from PyPi as nptime (“non-pedantic time”), or on GitHub: https://github.com/tgs/nptime
The documentation is at http://tgs.github.io/nptime/
You can change time() to now() for it to work
from datetime import datetime, timedelta
datetime.now() + timedelta(hours=1)
A little bit late to the party but you can also do something along the lines of:
init_time = time(4,0)
added_time = 8
new_time = datetime.time(init_time.hour+added_time)
Note that you’ll need to add in correction code to make sure init+time.hour + added+time do not go above 23,59.
I’m trying to do something like this:
time() + timedelta(hours=1)
however, Python doesn’t allow it, apparently for good reason.
Does anyone have a simple work around?
Related:
Workaround:
t = time()
t2 = time(t.hour+1, t.minute, t.second, t.microsecond)
You can also omit the microseconds, if you don’t need that much precision.
This is a bit nasty, but:
from datetime import datetime, timedelta
now = datetime.now().time()
# Just use January the first, 2000
d1 = datetime(2000, 1, 1, now.hour, now.minute, now.second)
d2 = d1 + timedelta(hours=1, minutes=23)
print d2.time()
The solution is in the link that you provided in your question:
datetime.combine(date.today(), time()) + timedelta(hours=1)
Full example:
from datetime import date, datetime, time, timedelta
dt = datetime.combine(date.today(), time(23, 55)) + timedelta(minutes=30)
print dt.time()
Output:
00:25:00
If it’s worth adding another file / dependency to your project, I’ve just written a tiny little class that extends datetime.time with the ability to do arithmetic. If you go past midnight, it just wraps around:
>>> from nptime import nptime
>>> from datetime import timedelta
>>> afternoon = nptime(12, 24) + timedelta(days=1, minutes=36)
>>> afternoon
nptime(13, 0)
>>> str(afternoon)
'13:00:00'
It’s available from PyPi as nptime (“non-pedantic time”), or on GitHub: https://github.com/tgs/nptime
The documentation is at http://tgs.github.io/nptime/
You can change time() to now() for it to work
from datetime import datetime, timedelta
datetime.now() + timedelta(hours=1)
A little bit late to the party but you can also do something along the lines of:
init_time = time(4,0)
added_time = 8
new_time = datetime.time(init_time.hour+added_time)
Note that you’ll need to add in correction code to make sure init+time.hour + added+time do not go above 23,59.