print() inside thread outputs wrong value

Question

I’m trying to recreate a stupid idea called sleep sort, however the output is far from expected.

I am expecting

However I get

…which is wierd because the thread does: sleep for (item) seconds and then print that item.

Here’s my code

import threading
import time

def sleepSort(lst):
    for item in lst:
        threading.Thread(target = lambda: (
            time.sleep(item),
            print(item)
        )).start()

sleepSort([3, 0, 2, 1, 5])

Is there something wrong with my code? Thank you very much in advance!

Asked By: kairo

||

Source

Answer 1

It’s typical behavior for many languages and caused by "late binding". You should pass argument explicitly to avoid this and also google something like "python late binding".

def sleepSort(lst):
    for item in lst:
        threading.Thread(target = lambda item: (
            time.sleep(item),
            print(item)
        ), args=(item, )).start()

Answered By: NobbyNobbs

print() inside thread outputs wrong value

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