passing parameters in neo4j using python

Question

I want to pass parameter in CREATE using Python
e.g:
”’

n = "abc"
a = 1234

cqlCreate = "CREATE (cornell:university { name: $n,yob:$a})"

””

but it dosen’t work.. any suggestions please

Asked By: Sama

||

Source

Answer 1

You can use the f-strings in Python. See example below. Note that

You need to use {{ as escape character for {

2 You need to use as escape character for "

n = "abc"
a = 1234

cqlCreate = f"CREATE (cornell:university {{name: "{n}", yob: {a}}})"
print (cqlCreate)

Result:
CREATE (cornell:university {name: "abc", yob: 1234})

reference: https://www.python.org/dev/peps/pep-0498/

Answered By: jose_bacoy

Answer 2

It actually depends on the Python driver that you are using to connect to Neo4j (check https://neo4j.com/developer/python/ to see the list of available drivers). If you are using the official neo4j-driver, the code you wrote is correct. In order execute the Cypher query, you could do something like this:

from neo4j import GraphDatabase

uri = # insert neo4j uri
user = # insert neo4j username
password = # insert neo4j password

n = "abc"
a = 1234
query = "CREATE (cornell:university { name: $n,yob:$a})"

driver = GraphDatabase.driver(uri, auth=(user, password))
session = driver.session()
result = session.run(query, n=n, a=a)
session.close()
driver.close()

Although âńōŋŷXmoůŜ’s answer will probably work, it is not recommended way to it.

See also:

https://neo4j.com/docs/api/python-driver/current/api.html

Answered By: Jaume Mateu

Answer 3

I had tried below format and was working perfectly for me. I am using neo4j 5.3.0

    info='Public'

    cypherQ= "MATCH  (n1{name:$info}), (a1{ID:'PL07227'}) RETURN exists( (n1)-[:my_dummy_relation]-(a1) )"

    session.run(cypherQ, info=info)

Answered By: Tono Kuriakose

passing parameters in neo4j using python

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