Sympy check if a number is natural

Question

If I some random number, how do I check if it’s an integer (∈ ℕ)?

>>> from sympy.core.numbers import Float
>>> Float(2)
2.00000000000000
>>> Float(2).is_integer
False # what ??

I’ve found a simple workaround but I feel It’s some kind of a hack:

>>> Float(2) % 1 == 0
True
>>> Float(2.5) % 1 == 0
False

So is there a more proper way of finding if a number is natural ?

Asked By: Amin Guermazi

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Source

Answer 1

This sort of query arises throughout the SymPy codebase and the solution that we have for this is to use as_int on the expression in question. When the strict flag is off, a float that is equivalent to the int will be returned as an int. Otherwise (or if the expression is not an integer) a ValueError will be raised:

>>> from sympy import Float
>>> from sympy.core.compatibility import as_int
>>> as_int(2.0)
Traceback (most recent call last):
... 
ValueError: 2.0 is not an integer

>>> as_int(2.0, strict=False)
2

Using this in a test function gives:

>>> def isint(i):
...     try: as_int(i, strict=False)
...     except: return False
...     return True
>>> isint(Float(2))
True

Another way to approach this is to check whether the decimal portion of a number is 0:

>>> (Float(2)%1).is_zero
True

Answered By: smichr

Sympy check if a number is natural

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