Python – Remove quotation marks from list

Question

I have a dataframe with a list of numbers. When printing the list there are quotation marks in the front and at the end which I want to remove.
I’m unable to replace them with the replace function.

a = df.iloc[0]['ids']
b = [a]
b (Output) 
['2769734487041924, 7608779650164612'] <-- one quotation mark at beginning and end

What I want (created manually):

row_ids = [1234, 4567]
row_ids (Output)
[1234, 4567] <-- That's the format I want to get the list to, without the quotation marks

Both b and row_ids data type comes back as ‘list’ so there must be a way to have the list without the quotation marks.

Asked By: TobeT

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Source

Answer 1

I think a is a string so to get b as a list of integers from that you need

b = list(map(int, a.split(",")))

Answered By: Joffan

Answer 2

Parse the string and split, Then use base ten to convert it as int.

lst = ['2769734487041924, 7608779650164612']
lst2 = []

for i in "".join(lst).split(","):
    lst2.append(int(i, base=10))
print(lst2)

Answered By: The.B

Answer 3

    lst = '['2769734487041924, 7608779650164612']'
    import json
    lst = json.loads(lst )
    lst = [int(item) for item in lst]

output:
lst = [2769734487041924, 7608779650164612]

Answered By: Fazi Alnjd

Python – Remove quotation marks from list

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