Examples for string find in Python

Question

I am trying to find some examples but no luck. Does anyone know of some examples on the net? I would like to know what it returns when it can’t find, and how to specify from start to end, which I guess is going to be 0, -1.

Asked By: Joan Venge

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Source

Answer 1

I’m not sure what you’re looking for, do you mean find()?

>>> x = "Hello World"
>>> x.find('World')
6
>>> x.find('Aloha');
-1

Answered By: Paolo Bergantino

Answer 2

you can use str.index too:

>>> 'sdfasdf'.index('cc')
Traceback (most recent call last):
  File "<pyshell#144>", line 1, in <module>
    'sdfasdf'.index('cc')
ValueError: substring not found
>>> 'sdfasdf'.index('df')
1

Answered By: SilentGhost

Answer 3

find( sub[, start[, end]])

Return the lowest index in the string where substring sub is found, such that sub is contained in the range [start, end]. Optional arguments start and end are interpreted as in slice notation. Return -1 if sub is not found.

From the docs.

Answered By: MarkusQ

Answer 4

Honestly, this is the sort of situation where I just open up Python on the command line and start messing around:

 >>> x = "Dana Larose is playing with find()"
 >>> x.find("Dana")
 0
 >>> x.find("ana")
 1
 >>> x.find("La")
 5
 >>> x.find("La", 6)
 -1

Python’s interpreter makes this sort of experimentation easy. (Same goes for other languages with a similar interpreter)

Answered By: Dana

Answer 5

From the documentation:

str.find(sub[, start[, end]])
Return the lowest index in the string where substring sub is found within the slice s[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 if sub is not found.

So, some examples:

>>> my_str = 'abcdefioshgoihgs sijsiojs '
>>> my_str.find('a')
0
>>> my_str.find('g')
10
>>> my_str.find('s', 11)
15
>>> my_str.find('s', 15)
15
>>> my_str.find('s', 16)
17
>>> my_str.find('s', 11, 14)
-1

Answered By: Phil H

Answer 6

If you want to search for the last instance of a string in a text, you can run rfind.

Example:

   s="Hello"
   print s.rfind('l')

output: 3

*no import needed

Complete syntax:

stringEx.rfind(substr, beg=0, end=len(stringEx))

Answered By: LucianNovo

Answer 7

Try this:

with open(file_dmp_path, 'rb') as file:
fsize = bsize = os.path.getsize(file_dmp_path)
word_len = len(SEARCH_WORD)
while True:
    p = file.read(bsize).find(SEARCH_WORD)
    if p > -1:
        pos_dec = file.tell() - (bsize - p)
        file.seek(pos_dec + word_len)
        bsize = fsize - file.tell()
    if file.tell() < fsize:
        seek = file.tell() - word_len + 1
        file.seek(seek)
    else:
        break

Answered By: Israel Alberto RV

Answer 8

if x is a string and you search for y which also a string their is two cases :
case 1: y is exist in x so x.find(y) = the index (the position) of the y in x .
case 2: y is not exist so x.find (y) = -1 this mean y is not found in x.

Answered By: N.Elsayed

Answer 9

Try

myString = 'abcabc'
myString.find('a')

This will give you the index!!!

Answered By: Dave Brown

Examples for string find in Python

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