TypeError: argument 1 must be pygame.Surface, not str , doesnt work

Question

This is the code ->

import pygame
import os

pygame.init()

width,height = (500,700)
bg=os.path.join('C:\Users\USER\Desktop\Python\picture match','background.jpg')
WIN = pygame.display.set_mode((width,height))



def draw():
    WIN.blit(bg,(0,0))
def main():

    run = True
    while run:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                run = False
                pygame.quit()

        draw()
main()

i have no clue why the error shows up, my previous projects have been working with this way.

Asked By: captainchungus

||

Source

Answer 1

bg is a string, containing the filename, but not an pygame.Surface object. Use pygame.image.load to load an image from a file source:

bbg_filename = os.path.join('C:\Users\USER\Desktop\Python\picture match','background.jpg')
bg = pygame.image.load(bg_filename)

Scale the background to the size of the window:

bg = pygame.transform.scale(bg, (width, height)).convert()

Update the display by calling either pygame.display.update() or pygame.display.flip() after drawing the scene:

draw()
pygame.display.flip()

Complete example:

import pygame
import os

pygame.init()

width,height = (500,700)
WIN = pygame.display.set_mode((width,height))

bg_filename = os.path.join('C:\Users\USER\Desktop\Python\picture match','background.jpg')
bg = pygame.image.load(bg_filename)
bg = pygame.transform.scale(bg, (width, height)).convert()

def draw():
    WIN.blit(bg,(0,0))
def main():

    run = True
    while run:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                run = False
                pygame.quit()

        draw()
        pygame.display.flip()
main()

Answered By: Rabbid76

TypeError: argument 1 must be pygame.Surface, not str , doesnt work

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