Convert any multi-dimensional numpy array to tuple of tuples of tuples… agnostic of number of dimensions

Question

That this answer to Convert numpy ndarray to tuple of tuples in optimize method doens’t offer anything more than tuple(tuple(i) for i in a[:,0,:]) suggests this doesn’t exist, but I am looking for something like a .totuple() method similar to numpy’s .tolist() in that you don’t need to know the number of dimensions beforehand to generate a tuple of tuples of tuples…

For my needs this would apply to a float or integer numerical array only.

Asked By: uhoh

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Source

Answer 1

You can make use of a recursive function which converts to a tuple independent of the number of dimensions:

def totuple(a):
    try:
        return tuple(totuple(i) for i in a)
    except TypeError:
        return a

Found in this answer:
Convert numpy array to tuple

Answered By: Jelle Westra

Answer 2

A more explicit alternative:

def totuple(a):
    if a.shape == ():
        return a.item()
    else:
        return tuple(map(totuple, a))

Example:

import numpy as np
a = np.arange(3 * 4).reshape(3, 4)
print(totuple(a))

((0, 1, 2, 3), (4, 5, 6, 7), (8, 9, 10, 11))

Answered By: user76284

Convert any multi-dimensional numpy array to tuple of tuples of tuples… agnostic of number of dimensions

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