Fastapi + Strawberry GraphQL

Question:

I’m currently building a microservice with fastapi.

I want to expose my underlying data via graphql on an additional route.
Direct integration from starlette has been deprecated so I tried to use one of the recommended packages strawberry.
At the moment, it seems impossible to use in combination with grapqhl.

Example

my_grapqhql.py

from typing import List
import strawberry

@strawberry.type
class Book:
    title: str
    author: str

@strawberry.type
class Query:
    books: List[Book]

schema = strawberry.Schema(query=Query)

What I tried

In the fastapi documentation, asgi components are added like so:

main.py

from fastapi import FastAPI
from strawberry.asgi import GraphQL
from .my_graphql.py import schema

app = FastAPI()
app.add_middleware(GraphQL, schema=schema)

Unfortunately this doesn’t work:

TypeError: __init__() got an unexpected keyword argument 'app'

when I switch the last line to mount a module is atleast starts:

app.mount("/graphql", GraphQL(schema))

but the route doesn’t load.

Asked By: gistBatch

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Source

Answers:

This has been documented here: https://strawberry.rocks/docs/integrations/fastapi#fastapi

From the docs

import strawberry

from fastapi import FastAPI
from strawberry.fastapi import GraphQLRouter


@strawberry.type
class Query:
    @strawberry.field
    def hello(self) -> str:
        return "Hello World"


schema = strawberry.Schema(Query)


graphql_app = GraphQLRouter(schema)


app = FastAPI()
app.include_router(graphql_app, prefix="/graphql")
Answered By: patrick

The new way of adding Strawberry with FastApi which is in documentation also

app = FastAPI()
schema = strawberry.Schema(query=Query,mutation=Mutation,config=StrawberryConfig(auto_camel_case=True))
graphql_app = GraphQLRouter(schema)
app.include_router(graphql_app, prefix="/graphql")
Answered By: SYED FAISAL