pythonic way to identify a local file or a url

Question

URL

http://www.example.com
www.example.com
http://example.com
https://example.com

LOCAL FILES

file:///example.html
/home/user/example.html
./home/user/example.html
.dir/data/example.html

Consider above input and identify whether given input string is local regular file or a URL?

What i have Tried

import os
from urllib.parse import urlparse

def is_local(_str):
    if os.path.exists(path1):
        return True
    elif urlparse(_str).scheme in ['','file']:
        return True
    return False

Call

is_local('file:///example.html')     # True
is_local('/home/user/example.html')  # True
is_local('./home/user/example.html') # True
is_local('.dir/data/example.html')   # True

is_local('http://www.example.com')   # False
is_local('www.example.com')          # True
is_local('http://example.com')       # False
is_local('https://example.com')      # False

Is there any pythonic way to identify a file is local or an URL without using urllib?

Asked By: ravishankar chavare

||

Source

Answer 1

You can use a combination of urllib.parse.urlpath and os.path.exists. The first extracts a file path from the URL, whilst the second checks if the path actually refers to a file.

from urllib.parse import urlparse
from os.path import exists

def is_local(url):
    url_parsed = urlparse(url)
    if url_parsed.scheme in ('file', ''): # Possibly a local file
        return exists(url_parsed.path)
    return False

Answered By: DYZ

pythonic way to identify a local file or a url

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