How can repetitive rows of data be collected in a single row in pandas?
Question:
I have a dataset that contains the NBA Player’s average statistics per game. Some player’s statistics are repeated because of they’ve been in different teams in season.
For example:
Player Pos Age Tm G GS MP FG
8 Jarrett Allen C 22 TOT 28 10 26.2 4.4
9 Jarrett Allen C 22 BRK 12 5 26.7 3.7
10 Jarrett Allen C 22 CLE 16 5 25.9 4.9
I want to average Jarrett Allen’s stats and put them into a single row. How can I do this?
Answers:
You can groupby
and use agg
to get the mean. For the non numeric columns, let’s take the first value:
df.groupby('Player').agg({k: 'mean' if v in ('int64', 'float64') else 'first'
for k,v in df.dtypes[1:].items()})
output:
Pos Age Tm G GS MP FG
Player
Jarrett Allen C 22 TOT 18.666667 6.666667 26.266667 4.333333
NB. content of the dictionary comprehension:
{'Pos': 'first',
'Age': 'mean',
'Tm': 'first',
'G': 'mean',
'GS': 'mean',
'MP': 'mean',
'FG': 'mean'}
x = [['a', 12, 5],['a', 12, 7], ['b', 15, 10],['b', 15, 12],['c', 20, 1]]
import pandas as pd
df = pd.DataFrame(x, columns=['name', 'age', 'score'])
print(df)
print('-----------')
df2 = df.groupby(['name', 'age']).mean()
print(df2)
Output:
name age score
0 a 12 5
1 a 12 7
2 b 15 10
3 b 15 12
4 c 20 1
-----------
score
name age
a 12 6
b 15 11
c 20 1
Option 1
If one considers the dataframe that OP shares in the question df
the following will do the work
df_new = df.groupby('Player').agg(lambda x: x.iloc[0] if pd.api.types.is_string_dtype(x.dtype) else x.mean())
[Out]:
Pos Age Tm G GS MP FG
Player
Jarrett Allen C 22.0 TOT 18.666667 6.666667 26.266667 4.333333
This one uses:
-
pandas.DataFrame.groupby
to group by the Player
column
-
pandas.core.groupby.GroupBy.agg
to aggregate the values based on a custom made lambda function.
-
pandas.api.types.is_string_dtype
to check if a column is of string type (see here how the method is implemented)
Let’s test it with a new dataframe, df2
, with more elements in the Player
column.
import numpy as np
df2 = pd.DataFrame({'Player': ['John Collins', 'John Collins', 'John Collins', 'Trae Young', 'Trae Young', 'Clint Capela', 'Jarrett Allen', 'Jarrett Allen', 'Jarrett Allen'],
'Pos': ['PF', 'PF', 'PF', 'PG', 'PG', 'C', 'C', 'C', 'C'],
'Age': np.random.randint(0, 100, 9),
'Tm': ['ATL', 'ATL', 'ATL', 'ATL', 'ATL', 'ATL', 'TOT', 'BRK', 'CLE'],
'G': np.random.randint(0, 100, 9),
'GS': np.random.randint(0, 100, 9),
'MP': np.random.uniform(0, 100, 9),
'FG': np.random.uniform(0, 100, 9)})
[Out]:
Player Pos Age Tm G GS MP FG
0 John Collins PF 71 ATL 75 39 16.123225 77.949756
1 John Collins PF 60 ATL 49 49 30.308092 24.788401
2 John Collins PF 52 ATL 33 92 11.087317 58.488575
3 Trae Young PG 72 ATL 20 91 62.862313 60.169282
4 Trae Young PG 85 ATL 61 77 30.248551 85.169038
5 Clint Capela C 73 ATL 5 67 45.817690 21.966777
6 Jarrett Allen C 23 TOT 60 51 93.076624 34.160823
7 Jarrett Allen C 12 BRK 2 77 74.318568 78.755869
8 Jarrett Allen C 44 CLE 82 81 7.375631 40.930844
If one tests the operation on df2
, one will get the following
df_new2 = df2.groupby('Player').agg(lambda x: x.iloc[0] if pd.api.types.is_string_dtype(x.dtype) else x.mean())
[Out]:
Pos Age Tm G GS MP FG
Player
Clint Capela C 95.000000 ATL 30.000000 98.000000 46.476398 17.987104
Jarrett Allen C 60.000000 TOT 48.666667 19.333333 70.050540 33.572896
John Collins PF 74.333333 ATL 50.333333 52.666667 78.181457 78.152235
Trae Young PG 57.500000 ATL 44.500000 47.500000 46.602543 53.835455
Option 2
Depending on the desired output, assuming that one only wants to group by player (independently of Age
or Tm
), a simpler solution would be to just group by and pass .mean()
as follows
df_new3 = df.groupby('Player').mean()
[Out]:
Age G GS MP FG
Player
Jarrett Allen 22.0 18.666667 6.666667 26.266667 4.333333
Notes:
- The output of this previous operation won’t display non-numerical columns (apart from the Player name).
I have a dataset that contains the NBA Player’s average statistics per game. Some player’s statistics are repeated because of they’ve been in different teams in season.
For example:
Player Pos Age Tm G GS MP FG
8 Jarrett Allen C 22 TOT 28 10 26.2 4.4
9 Jarrett Allen C 22 BRK 12 5 26.7 3.7
10 Jarrett Allen C 22 CLE 16 5 25.9 4.9
I want to average Jarrett Allen’s stats and put them into a single row. How can I do this?
You can groupby
and use agg
to get the mean. For the non numeric columns, let’s take the first value:
df.groupby('Player').agg({k: 'mean' if v in ('int64', 'float64') else 'first'
for k,v in df.dtypes[1:].items()})
output:
Pos Age Tm G GS MP FG
Player
Jarrett Allen C 22 TOT 18.666667 6.666667 26.266667 4.333333
NB. content of the dictionary comprehension:
{'Pos': 'first',
'Age': 'mean',
'Tm': 'first',
'G': 'mean',
'GS': 'mean',
'MP': 'mean',
'FG': 'mean'}
x = [['a', 12, 5],['a', 12, 7], ['b', 15, 10],['b', 15, 12],['c', 20, 1]]
import pandas as pd
df = pd.DataFrame(x, columns=['name', 'age', 'score'])
print(df)
print('-----------')
df2 = df.groupby(['name', 'age']).mean()
print(df2)
Output:
name age score
0 a 12 5
1 a 12 7
2 b 15 10
3 b 15 12
4 c 20 1
-----------
score
name age
a 12 6
b 15 11
c 20 1
Option 1
If one considers the dataframe that OP shares in the question df
the following will do the work
df_new = df.groupby('Player').agg(lambda x: x.iloc[0] if pd.api.types.is_string_dtype(x.dtype) else x.mean())
[Out]:
Pos Age Tm G GS MP FG
Player
Jarrett Allen C 22.0 TOT 18.666667 6.666667 26.266667 4.333333
This one uses:
-
pandas.DataFrame.groupby
to group by thePlayer
column -
pandas.core.groupby.GroupBy.agg
to aggregate the values based on a custom made lambda function. -
pandas.api.types.is_string_dtype
to check if a column is of string type (see here how the method is implemented)
Let’s test it with a new dataframe, df2
, with more elements in the Player
column.
import numpy as np
df2 = pd.DataFrame({'Player': ['John Collins', 'John Collins', 'John Collins', 'Trae Young', 'Trae Young', 'Clint Capela', 'Jarrett Allen', 'Jarrett Allen', 'Jarrett Allen'],
'Pos': ['PF', 'PF', 'PF', 'PG', 'PG', 'C', 'C', 'C', 'C'],
'Age': np.random.randint(0, 100, 9),
'Tm': ['ATL', 'ATL', 'ATL', 'ATL', 'ATL', 'ATL', 'TOT', 'BRK', 'CLE'],
'G': np.random.randint(0, 100, 9),
'GS': np.random.randint(0, 100, 9),
'MP': np.random.uniform(0, 100, 9),
'FG': np.random.uniform(0, 100, 9)})
[Out]:
Player Pos Age Tm G GS MP FG
0 John Collins PF 71 ATL 75 39 16.123225 77.949756
1 John Collins PF 60 ATL 49 49 30.308092 24.788401
2 John Collins PF 52 ATL 33 92 11.087317 58.488575
3 Trae Young PG 72 ATL 20 91 62.862313 60.169282
4 Trae Young PG 85 ATL 61 77 30.248551 85.169038
5 Clint Capela C 73 ATL 5 67 45.817690 21.966777
6 Jarrett Allen C 23 TOT 60 51 93.076624 34.160823
7 Jarrett Allen C 12 BRK 2 77 74.318568 78.755869
8 Jarrett Allen C 44 CLE 82 81 7.375631 40.930844
If one tests the operation on df2
, one will get the following
df_new2 = df2.groupby('Player').agg(lambda x: x.iloc[0] if pd.api.types.is_string_dtype(x.dtype) else x.mean())
[Out]:
Pos Age Tm G GS MP FG
Player
Clint Capela C 95.000000 ATL 30.000000 98.000000 46.476398 17.987104
Jarrett Allen C 60.000000 TOT 48.666667 19.333333 70.050540 33.572896
John Collins PF 74.333333 ATL 50.333333 52.666667 78.181457 78.152235
Trae Young PG 57.500000 ATL 44.500000 47.500000 46.602543 53.835455
Option 2
Depending on the desired output, assuming that one only wants to group by player (independently of Age
or Tm
), a simpler solution would be to just group by and pass .mean()
as follows
df_new3 = df.groupby('Player').mean()
[Out]:
Age G GS MP FG
Player
Jarrett Allen 22.0 18.666667 6.666667 26.266667 4.333333
Notes:
- The output of this previous operation won’t display non-numerical columns (apart from the Player name).