Keras AttributeError: 'Sequential' object has no attribute 'predict_classes'

Question:

Im attempting to find model performance metrics (F1 score, accuracy, recall) following this guide https://machinelearningmastery.com/how-to-calculate-precision-recall-f1-and-more-for-deep-learning-models/

This exact code was working a few months ago but now returning all sorts of errors, very confusing since i havent changed one character of this code. Maybe a package update has changed things?

I fit the sequential model with model.fit, then used model.evaluate to find test accuracy. Now i am attempting to use model.predict_classes to make class predictions (model is a multi-class classifier). Code shown below:

model = Sequential()
model.add(Dense(24, input_dim=13, activation='relu'))
model.add(Dense(18, activation='relu'))
model.add(Dense(6, activation='softmax'))
model.compile(loss='categorical_crossentropy', optimizer='adam', metrics=['accuracy'])

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history = model.fit(X_train, y_train, batch_size = 256, epochs = 10, verbose = 2, validation_split = 0.2)

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score, acc = model.evaluate(X_test, y_test,verbose=2, batch_size= 256)
print('test accuracy:', acc)

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yhat_classes = model.predict_classes(X_test)
 

last line returns error "AttributeError: ‘Sequential’ object has no attribute ‘predict_classes’"

This exact code was working not long ago so struggling a bit, thanks for any help

Asked By: Greig Fotheringham

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Answers:

This function was removed in TensorFlow version 2.6.
According to the keras in rstudio reference

update to

predict_x=model.predict(X_test) 
classes_x=np.argmax(predict_x,axis=1)

Or use TensorFlow 2.5.x .

If you are using TensorFlow version 2.5, you will receive the following warning:

tensorflowpythonkerasenginesequential.py:455: UserWarning: model.predict_classes() is deprecated and will be removed after 2021-01-01. Please use instead:* np.argmax(model.predict(x), axis=-1), if your model does multi-class classification (e.g. if it uses a softmax last-layer activation).* (model.predict(x) > 0.5).astype("int32"), if your model does binary classification (e.g. if it uses a sigmoid last-layer activation).

Answered By: Xueke

I used following code for predictions

y_pred = model.predict(X_test)
y_pred = np.round(y_pred).astype(int)
Answered By: arun

I experienced the same error, I use this following code, and succeed

Replaced:

predictions = model.predict_classes(x_test)

With this one:

predictions = (model.predict(x_test) > 0.5).astype("int32")

Type of python packages : Tensorflow 2.6.0

Answered By: M.Nuramzan Iftari

We can replace the problematic code line with the following:

y_predict = np.argmax(model.predict(x_test), axis=-1)
Answered By: Jaden Tseng

In the newest version of Tensorflow, the predict_classes function has been deprecated (there was a warning in previous versions about this). The new syntax is as follows:

predictions = np.argmax(model.predict(x_test),axis=1)
Answered By: Quantum Prophet

In Tensorflow 2.7 predicted classes can be obtained with the following code:

    predicted = np.argmax(model.predict(token_list),axis=1)
Answered By: Abhinand P

Use this as the predict_classes are removed with the latest version of tensorflow

predictions = (model.predict(X_test) > 0.5)*1 

Since this is a binary problem (0 or 1), the output class is determined by whether the probability is bigger than 0.5. Hence the code above

For this code below for an entire dataset,

preds = model.predict_classes(test_sequences)

This code can be used for the new versions.

y_predict = np.argmax(model.predict(test_sequences), axis=1)

In this, the "test_sequence" is the data frame u have to predict, and the axis is to choose either columns or rows.

Answered By: Nishad Ahamed

If you are using a multi-class classification then use
np.argmax(model.predict(x), axis=-1)

for example :

predictions = np.argmax(model.predict(x_test),axis=1)

Or else if you have a Binary classification problem at hand use (model.predict(x) > 0.5).astype("int32")

for example :

`predictions=(model.predict(X_test) > 0.5).astype("int32")`
Answered By: arash

I use this and worked:

y_pred_prob = model.predict(X_test)
y_pred = np.round(y_pred_prob)
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