Is there a way to run flask in debug mode using the `flask run` command without setting environment variables?

I’m trying to run a flask application in debug mode (or at least a mode where it will reload after changing the files).

I’m aware of export FLASK_ENV=development, however I am working on a university online development environment, and I lose the environment variables every time the site reloads, which while not the end of the world, is slightly annoying, and I’d rather avoid having to keep typing it (lazy I know).

If I include the following, and run using python3 main.py, debug mode is activated, however when using flask run, debug remains off.

if __name__ == "__main__":
  app.run(debug=True)

However, as I understand it, using the flask run command is the preferred way to launch the app, not using python app.py.

I’ve found ideas such as including the following, however none of these have activated debug mode, so I’m wondering whether it is even possible:

app.config['ENV'] = 'development'
app.config['DEBUG'] = True
app.config['TESTING'] = True

I’ve simplified my code to the following to see if it was an error in my original piece, but it doesn’t seem to be:

from flask import Flask

app = Flask(__name__)
app.config['ENV'] = 'development'
app.config['DEBUG'] = True
app.config['TESTING'] = True

@app.route('/')
def home():
    return '<h1>debugging!</h1>'

if __name__ == "__main__":
    app.run(debug=True)