How to handle flexible inputs and returns only keys in uppercase?

Question

The ideal output or results should be like below:

    >>> uppercase_keys_from_kwargs(twn='Taiwan')
    ['TWN']
    >>> uppercase_keys_from_kwargs(twn='Taiwan', jpn='Japan')
    ['TWN', 'JPN']
    >>> uppercase_keys_from_kwargs(twn='Taiwan', jpn='Japan', ltu="Lithuania")
    ['TWN', 'JPN', 'LTU']
    >>> uppercase_keys_from_kwargs(twn='Taiwan', jpn='Japan', ltu="Lithuania", svn='Slovenia')
    ['TWN', 'JPN', 'LTU', 'SVN']

My Code just able obtain the keys only:

def uppercase_keys_from_kwargs(**kwargs) -> list:
keys_only = kwargs.keys()
list_for_keys_only = list(keys_only)

return(list_for_keys_only)

My output:

>>> print(uppercase_keys_from_kwargs(twn='Taiwan'))
['twn']
>>> print(uppercase_keys_from_kwargs(twn='Taiwan', jpn='Japan'))
['twn', 'jpn']
>>> print(uppercase_keys_from_kwargs(twn='Taiwan', jpn='Japan', ltu="Lithuania"))
['twn', 'jpn', 'ltu']
>>> print(uppercase_keys_from_kwargs(twn='Taiwan', jpn='Japan', ltu="Lithuania", svn='Slovenia'))
['twn', 'jpn', 'ltu', 'svn']

Tried to add something like this:

# for k in kwargs.items():
    #     kwargs.update(k.upper())

but did not work. Appear to be an AttributeError.

Asked By: PTP_XX

||

Source

Answer 1

We can use map with str.upper on dict.keys.

def uppercase_keys_from_kwargs(**kwargs):
    return list(map(str.upper, kwargs.keys()))

Ouput:

uppercase_keys_from_kwargs(twn='Taiwan')
# ['TWN']

uppercase_keys_from_kwargs(
    twn="Taiwan", jpn="Japan", ltu="Lithuania", svn="Slovenia"
)
# ['TWN', 'JPN', 'LTU', 'SVN']

Answered By: Ch3steR

Answer 2

Try out this:

def uppercase_keys_from_kwargs(**kwargs) -> list:
    keys_only = kwargs.keys()
    list_for_keys_only = [k.upper() for k in keys_only]

    return(list_for_keys_only)

    
print (uppercase_keys_from_kwargs(twn='Taiwan', jpn='Japan', ltu="Lithuania"))

Output:

['TWN', 'JPN', 'LTU']

Answered By: Bhagyesh Dudhediya

How to handle flexible inputs and returns only keys in uppercase?

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