Python | Using datetime to determine whether the US stock market is open, logic not working correctly

Question

I have this block of code that is supposed to be mentioning whether the stock market is open or not. Holidays aren’t included yet.

current_time = datetime.now()
local_date = datetime.strftime(current_time, '%b %d, %Y')
print("Today's date is: " + str(local_date))

#Prints out the time on the east coast. Helps give context on market hours.    
eastern_time = datetime.strftime(current_time.astimezone(pytz.timezone('US/Eastern')), '%I:%M %p')

print("Time on the East Coast is currently: " + eastern_time)
day_of_week = datetime.strftime(current_time.astimezone(pytz.timezone('US/Eastern')), '%A')
print(day_of_week)
dt_east = int(datetime.strftime(current_time.astimezone(pytz.timezone('US/Eastern')), '%H%M'))
print(dt_east)
if 930 <= dt_east <= 1600 and (day_of_week != "Saturday" or day_of_week != "Sunday"):
    print("The market is open!")
else:
    print("The market is closed.")

Output:

Today's date is: Nov 07, 2021
Time on the East Coast is currently: 12:01 PM
Sunday
1213
The market is open!

Printing out day_of_week even shows that it’s Sunday but returns that the market is open. I ran a quick True/False test and it returns True that it is in fact Sunday.
Not sure what else to try.

Asked By: squarehammer89

||

Source

Answer 1

# consider the below portion of your if 
(day_of_week != "Saturday" or day_of_week != "Sunday")

It returns True if either day_of_week != "Saturday" or day_of_week != "Sunday" is True.

Which means, if the day is Sunday, day_of_week != "Saturday" still return True and so the total output is still True

You need to replace the or with and

# if 930 <= dt_east <= 1600 and (day_of_week != "Saturday" or day_of_week != "Sunday")
if (930 <= dt_east <= 1600) and (day_of_week != "Saturday") and (day_of_week != "Sunday")

Answered By: Muhd Mairaj

Answer 2

from datetime import date, timedelta
import pandas_market_calendars as mcal

today_str = date.today().strftime("%Y-%m-%d")
start_date = date.today() - timedelta(days = 3)
end_date = date.today() + timedelta(days = 5)
nyse = mcal.get_calendar('NYSE')
nyse_schedule = nyse.schedule(start_date=start_date, end_date=end_date)
display(nyse_schedule)
if today_str in nyse_schedule.index:
    print(f"Today {today_str} stock market is open.")
    market_status = 1
else:
    print(f"Today {today_str} stock market is NOT open.")
    market_status = 0

Answered By: Anthony Stoyanov

Answer 3

A simple function that takes a datetime and returns a boolean

import pytz
from datetime import datetime

def is_market_opened(dt: datetime) -> bool:
    dt = dt.astimezone(pytz.timezone('America/New_York'))
    return 0 <= dt.weekday() <= 4 and 9*60+30 <= dt.hour*60+dt.minute <= 16*60

Answered By: fbattello

Python | Using datetime to determine whether the US stock market is open, logic not working correctly

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