dictionary keys() and values() relationship

Question

I have some dictionary d.

k = d.keys()
v = d.values()

Is there a guarantee that k[n] and v[n] are related, for every n?

Asked By: Tony Ennis

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Source

Answer 1

According to this answer on a related question, dictionaries maintain insertion order as of Python 3.6. Here is a link to Guido’s decree to "make it so".

Here is an example I did in the Python3 console to test that the relationship for every n is related:

>>> a = dict()
>>> a['yes'] = 'no'
>>> a['blah'] = 'beeper'
>>> a['foo'] = 'bar'
>>> a.keys()
dict_keys(['yes', 'blah', 'foo'])
>>> a.values()
dict_values(['no', 'beeper', 'bar'])
>>>

Edit: After reading some of the comments above, you would need to make these into lists to access them as indexes. So following that from the previous example:

>>> keys = list(a.keys())
>>> keys
['yes', 'blah', 'foo']
>>> values = list(a.values())
>>> values
['no', 'beeper', 'bar']

Answered By: Milo Fultz

Answer 2

Yes. Corresponding entries from .keys() and .values() represent the same key/value pair within the dictionary. (In older versions of Python, the orders may vary if you add or remove items, but they correspond if no such modifications are made between calls.)

d = {"answer": 42, "unlucky": 13, ...}
assert list(d.items()) == list(zip(d.keys(), d.values()))

This was made explicit in previous versions of the Python documentation. In recent versions of Python, where items retain their insertion order regardless of changes to the dictionary, they apparently didn’t feel it needed to be made explicit, but it’s still true.

Python dictionary: are keys() and values() always the same order?

Answered By: kindall

Answer 3

a = dict()
a["sas"] = 10
a["ase"] = 90
a["ing"] = 98
print(a)

And the keys on its own!

print(a[0])
print(a[1])
print(a[2])

Answered By: gz200

dictionary keys() and values() relationship

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