How would I compute exactly 30 days into the past with Python (down to the minute)?
Question:
In Python, I’m attempting to retrieve the date/time that is exactly 30 days (30*24hrs) into the past. At present, I’m simply doing:
>>> import datetime
>>> start_date = datetime.date.today() + datetime.timedelta(-30)
Which returns a datetime object, but with no time data:
>>> start_date.year
2009
>>> start_date.hour
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'datetime.date' object has no attribute 'hour'
Answers:
You want to use a datetime
object instead of just a date
object:
start_date = datetime.datetime.now() - datetime.timedelta(30)
date
just stores a date and time
just a time. datetime
is a date with a time.
In Python, I’m attempting to retrieve the date/time that is exactly 30 days (30*24hrs) into the past. At present, I’m simply doing:
>>> import datetime
>>> start_date = datetime.date.today() + datetime.timedelta(-30)
Which returns a datetime object, but with no time data:
>>> start_date.year
2009
>>> start_date.hour
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'datetime.date' object has no attribute 'hour'
You want to use a datetime
object instead of just a date
object:
start_date = datetime.datetime.now() - datetime.timedelta(30)
date
just stores a date and time
just a time. datetime
is a date with a time.