How to get dictionary keys using a tuple, where dictionary keys are stored in list and values in tuple

Question

dictionary = {}

my_list = ['a','b','c','d']

for i in range(len(my_list)-1):
    dictionary[my_list[i]] = (my_list[i],)


for i in sorted (dictionary.keys()):
    k = dictionary[i]
    """code here"""

For the above code I need to get the output as :
a
b
c

I know if we put print(i), we will get the desired output, but the answer expected is in terms of K.
Actual answer is: print(k[0]),which I am unable to understand.

Thanks

Asked By: Praveen Paliwal

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Source

Answer 1

Since you define values of dictionary equal to a tuple here:

dictionary[my_list[i]] = (my_list[i],)

k is a tuple which means for it to print the actual value you need to get the first item in k by using the following:

dictionary = {}

my_list = ['a','b','c','d']

for i in range(len(my_list)-1):
    dictionary[my_list[i]] = (my_list[i],)


for i in sorted (dictionary.keys()):
    k = dictionary[i]
    print(k[0])

Output:

a
b
c

k[0] just gets the first item in the tuple ('a',). This makes it print a instead of ('a',).

Answered By: Eli Harold

How to get dictionary keys using a tuple, where dictionary keys are stored in list and values in tuple

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