Printing a zip from dictionary return Empty list

Question

I am performing this simple zip in python from a dictionary and I am not sure why the second time I do it it gives me an empty list.

l1= {'a':6, 'b':5, 'c':3, 'd':2, 'e':1, 'f':7, 'g':4, 'h':9}
l2={'a':7, 'b':5, 'c':2, 'd':3, 'e':8}

z=zip(l1.values(),l2.values())

print(list(z)) #This gives me correct output.
print(list(z)) #This gives me EMPTY list. WHY?

[(6, 7), (5, 5), (3, 2), (2, 3), (1, 8)]
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Asked By: Arpit

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Source

Answer 1

you can use zip one time because it iter object

you can convert it to list object

import copy
l1= {'a':6, 'b':5, 'c':3, 'd':2, 'e':1, 'f':7, 'g':4, 'h':9}
l2={'a':7, 'b':5, 'c':2, 'd':3, 'e':8}

z=list(zip(l1.values(),l2.values()))
print(list(z)) #This gives me correct output.
print(list(z)) #This gives me EMPTY list. WHY?

output

[(6, 7), (5, 5), (3, 2), (2, 3), (1, 8)]
[(6, 7), (5, 5), (3, 2), (2, 3), (1, 8)]

Answered By: tomerar

Printing a zip from dictionary return Empty list

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