Python: Sort a list and print it out with a for loop – 'NoneType' object is not iterable'

Question

I have created a random list with numbers:

numbers = [8, 2, 17, 99, 12]

And I want to print them out with a for loop and permanently sort the numbers in increasing order.

I was able to do that, but i’m not sure if I am using the short way to do that.

numbers.sort()
for number in numbers:
   print (number)

I solved that with the code above, but my first instict was to do this:

for number in numbers.sort():
   print (number)

But the following error was found: TypeError: ‘NoneType’ object is not iterable.

Is there a way to sort the numbers in the "for placeholder_variable in variable" or the only way is with the first code? I have to sort them first and then make the for loop?

Thank you.

Asked By: DR8

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Source

Answer 1

what you want is:

for number in sorted(numbers):
   print (number)

numbers.sort() sorts your list in place but does not return anything itself.

Answered By: Max Power

Python: Sort a list and print it out with a for loop – 'NoneType' object is not iterable'

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