sqlalchemy: get max/min/avg values from a table

Question

I have this query:

mps =   (
            session.query(mps)  .filter_by(idc = int(c.idc))
                                .filter_by(idmp = int(m.idmp))
                                .group_by(func.day(mps.tschecked))
        ).all()

My problem is, that I don’t know how to extract (with sqlalchemy) the max/min/avg value from a table…

I find this: Database-Independent MAX() Function in SQLAlchemy

But I don’t know where to use this func.max/min/avg…

Can someone tell me how to do this? Can you give me an example?

Asked By: Wolfy

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Source

Answer 1

The following functions are available with from sqlalchemy import func:

func.min
func.max
func.avg

Documentation is available here.

You can use them i.e. in the query() method.

Example:

session.query(self.stats.c.ID, func.max(self.stats.c.STA_DATE))

(just like you use aggregate functions in plain SQL)

Answered By: Archarius

Answer 2

Or just use an order_by() and select the first or last element. . .

Answered By: reptilicus

sqlalchemy: get max/min/avg values from a table

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