Capturing a function call as dict

Question

I’m trying to write a python function decorator, and part of my implementation is that I need to capture the function call and look through the supplied values. I already have the function signature by using inspect.signature, but I’m unsure how to compose it with passed arguments.

Say I had the following

def decorator(func):
    def wrapper(*args, **kwargs):
        print(some_function_signature_getter(func, *args, **kwargs))
        return func(*args, **kwargs)
    return wrapper


@decorator
def foo(a, b, *_, **kwargs):
    return a+b

print(foo(1, 2))

How can I implement some_function_signature_getter such that my output is something like the following:

{'a': 1, 'b': 2, '_':[], 'kwargs':{}}
3

Asked By: user852541

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Source

Answer 1

Whenever you want to introspect function/method signatures, you can use inspect.signature. In this case:

from inspect import signature

def decorator(func):
    sig = signature(func)
    def wrapper(*args, **kwargs):
        bound = sig.bind(*args, **kwargs)
        bound.apply_defaults()
        print(bound.arguments)
        return func(*args, **kwargs)
    return wrapper

*args are a tuple, not a list, but otherwise this gives you what you want:

>>> print(foo(1, 2))
{'a': 1, 'b': 2, '_': (), 'kwargs': {}}
3

Answered By: jonrsharpe

Capturing a function call as dict

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