Regex to get all items between '#' and unknown character

Question

I have a string that will have a value somewhere along the lines of

#549382This/ *is a test&

And I want to remove the #549382 from the text.

I know there are a lot of questions about regex and I have looked at this one specifically which would work if I knew the character to remove. But any letter or symbol can follow that string of numbers. I need a way to be able to say

Give me all characters between the ‘#’ and the first letter

What the letter is does not matter but it can be any non-digit character or letter.

For example

#549382This is a test         ->    This is a test
#71290571Another test here    ->    Another test here
#276//a comment as well       ->    //a comment as well

Asked By: Luke

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Source

Answer 1

Try something like this. can put it in a loop or whatever

import re
teststr='#549382This is a test'

e='#[0-9]*(.*)'

re.findall(e,teststr)

Answered By: SuperStew

Answer 2

As for your question, ‘Give me all characters between the ‘#’ and the first letter what the letter is does not matter but it can be any alphabetical number, meaning any non-digit character.’, the following code will do:

import re

cases = [
    "#549382This is a test",
    "#71290571Another test",
    "#276//a comment as well",
]
regex_pattern = '#(d+)'
for case in cases:
    number = re.findall(regex_pattern, case)
    print(number)

>>> ['549382']
>>> ['71290571']
>>> ['276']

Explaination: The regex will all digits (d+) after the # and up to any non-digit character.

Answered By: Steinn Hauser Magnusson

Answer 3

you can use regex like this

import re
string = '#549382This is a test'
result = re.sub('^#d*', '', string)
This is a test

Answered By: Naser Hussain

Regex to get all items between '#' and unknown character

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