Take some inputs until 0 encountered, print each word in lowercase and break the loop
Question:
Write a program to input the lines of text, print them to the screen after converting them to lowercase. The last line prints the number of input lines.
The program stops when it encounters a line with only zero.
Requirements: use infinite loop and break . statement
here’s my code but it’s saying Input 9 is empty
a = 1
l = 0
while a != 0:
a = input()
a.lower()
print(a)
l+=1
example inputs
TbH
Rn
ngL
bRb
0
Answers:
There a few errors in your original code, here is some suggestions and fixes. This post is try to follow your code as much as it can, and point the changes needed.
Please see the comments and ask if you have any questions.
count = 0 # to count the lines
while w != '0': # input's string
w = input().strip() # get rid of n space
word = w.lower() # convert to lower case
print(word)
count += 1
# while-loop stops once see '0'
Outputs: (while running)
ABBA
abba
Misssissippi
misssissippi
To-Do
to-do
0
0
This may accomplish what you are trying to achieve:
def infinite_loop():
while True:
user_input = input('enter a value:n> ')
if user_input == '0':
break
else:
print(user_input.lower())
if __name__ == '__main__':
infinite_loop()
I’d suggest this, it’s a combination of these 2 comments, sorry
count = 0
while True:
a = input()
if a == '0':
break
else:
print(a.lower())
count += 1
print(count)
Write a program to input the lines of text, print them to the screen after converting them to lowercase. The last line prints the number of input lines.
The program stops when it encounters a line with only zero.
Requirements: use infinite loop and break . statement
here’s my code but it’s saying Input 9 is empty
a = 1
l = 0
while a != 0:
a = input()
a.lower()
print(a)
l+=1
example inputs
TbH
Rn
ngL
bRb
0
There a few errors in your original code, here is some suggestions and fixes. This post is try to follow your code as much as it can, and point the changes needed.
Please see the comments and ask if you have any questions.
count = 0 # to count the lines
while w != '0': # input's string
w = input().strip() # get rid of n space
word = w.lower() # convert to lower case
print(word)
count += 1
# while-loop stops once see '0'
Outputs: (while running)
ABBA
abba
Misssissippi
misssissippi
To-Do
to-do
0
0
This may accomplish what you are trying to achieve:
def infinite_loop():
while True:
user_input = input('enter a value:n> ')
if user_input == '0':
break
else:
print(user_input.lower())
if __name__ == '__main__':
infinite_loop()
I’d suggest this, it’s a combination of these 2 comments, sorry
count = 0
while True:
a = input()
if a == '0':
break
else:
print(a.lower())
count += 1
print(count)