count uniq ids between column and index (like pivot table)

Question

I have a table:

id	Name
1	A
2	A
2	B
2	C
3	B
3	C
4	C
4	A

And I need a new table where unique IDs are calculated at the intersection of names. That is, for example, ID 2 has both A and B, that is, at the intersection of A and B, there is already one ID. Something like this:

Name	A	B	C
A	–	1	2
B	1	–	2
C	2	2	–

I tried with pandas.pivot_table, but i couldn’t understand how

Asked By: Diana Bugrimova

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Source

Answer 1

Let us use crosstab to create frequency table, then calculate the inner product to generate similarity / intersection matrix and mask the diagonal values with 0

s = pd.crosstab(df['Name'], df['id']).clip(upper=1)
s = s @ s.T
np.fill_diagonal(s.values, 0)

print(s)

Name  A  B  C
Name         
A     0  1  2
B     1  0  2
C     2  2  0

Answered By: Shubham Sharma

count uniq ids between column and index (like pivot table)

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