how to remove an item in a list of list of string using index in python

Question

input:

letters = [['a', 'b', 'c'], ['a', 'b', 'c']]
row= 0
column=0

output

[['b', 'c'], ['a', 'b', 'c']]

I tried to do this:

letters[0].remove(0)

but it gives me a value error, while when I use pop like this:

letters[0].pop(0)

it does what I need but the problem with pop is that it returns me something while I just need the item to be removed

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Answer 1

letters = [['a', 'b', 'c'], ['a', 'b', 'c']]

del list1[0][0]

use the del keyword

Answered By: Caleb Bunch

Answer 2

list.remove() removes an item by value, not by index. So letters[0].remove('b') would work.
Simply deleting a single element with the same syntax, you could address it in any other statement is del which could be used as del letters[0][0]
As @Barmar said: list.pop) can return an element by index and remove it from the list.

Answered By: Niclas

Answer 3

You can try this if you want to delete the element by index value of the list:

del letters[0][0]  # [['b', 'c'], ['a', 'b', 'c']]
del letters[1][0]  # [['a', 'b', 'c'], ['b', 'c']]

or if you want remove specific value in the first occurance:

letters[0].remove('a')  # [['b', 'c'], ['a', 'b', 'c']]
letters[1].remove('a')  # [['a', 'b', 'c'], ['b', 'c']]

Answered By: A. N. C.

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