How to normalize text with regex?

Question:

How to normilize text with regex with some if statements?

If we have string like this
One T933 two, three35.4. four 9,3 8.5 five M2x13 M4.3x2.1

And I want to normilize like this
one t 933 two three 35.4 four 9,3 8.5 five m2x13 m4.3x2.1

  1. Remove all dots and commas.
  2. Split number and string if not starts with letter ‘M’ T933 –> T 933
  3. All lowercase
  4. Do not split if there is dot or comma between numbers 35.4 –> 35.4 or 9,3 –> 9.3 if there is comma between, then replace to dot

What I am able to do is this

def process(str, **kwargs):
    str = str.replace(',', '.')
    str = re.split(r'(-?d*.?d+)', str)
    str = ' '.join(str)
    str.lower()
    return str

but there is no if condition when numbers starts with letter ‘M’ and their also is splitted.
And in some reason after string process i get some unnecessary spaces.

Is there some ideas how to do that with regex? Or with help methods like replace, lower, join and so on?

Asked By: Dmiich

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Answers:

I can suggest a solution like

re.sub(r'[.,](?!(?<=d.)d)', '', re.sub(r'(?<=[^Wd_])(?<![MmXx])(?=d)|(?<=d)(?=[^Wd_])', ' ', text)).lower()

The outer re.sub is meant to remove dots or commas when not between digits:

  • [.,] – a comma or dot
  • (?!(?<=d.)d) – a negative lookahead that fails the match if there is a digit immediately to the right, that is immediately preceded with a digit + any one char

The inner re.sub replaces with a space the following pattern:

  • (?<=[^Wd_])(?<![MmXx])(?=d) – a location between a letter ([^Wd_] matches any letter) and a digit (see (?=d)), where the letter is not M or X (case insensitive, [MmXx] can be written as (?i:[mx]))
  • | – or
  • (?<=d)(?=[^Wd_]) – a location between a digit and a letter.

See the Python demo:

import re
text = 'One T933 two, three35.4. four 9,3 8.5 five M2x13 M4.3x2.1 aa88aa'
print( re.sub(r'[.,](?!(?<=d.)d)', '', re.sub(r'(?<=[^Wd_])(?<![MmXx])(?=d)|(?<=d)(?=[^Wd_])', ' ', text)).lower() )

Output:

one t 933 two three 35.4 four 9,3 8.5 five m2 x13 m4.3 x2.1 aa 88 aa
Answered By: Wiktor Stribiżew
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